问题
I am writing the logic for an edit form and have some complications when displaying data in the inputs.
When I initially show the form, I show the records values like:
value="{{$dog->title}}"
Then when the form does not pass the validation I need to show the old input, so that user does not loose what he has already input. So I need to have a way to display old data like:
value="{{old('title')}}"
Because I need to input old data in case it exists, I ended up with this code:
value="{{$dog->title or old('title')}}"
And in controller I check if Request has old input, I assign the $dog var a null value.
I wanted to ask if that is considered an OK practice or is there a better and 'correct' way to do it?
回答1:
Function old have default parameter if no old data found in session.
function old($key = null, $default = null)
You can replace expression in template with
value="{{old('title', $dog->title)}}"
回答2:
I know this has already been answered but I thought i would leave a little snippet here for others in the future.
Setting old value on input as @ikurcubic posted can be used the same way on radio button or select:
<input type="text" name="name" value="{{ old('name', $DB->default-value) }}" />
Select option:
<option value="Jeff" {{ old('name', $DB->default-value) == 'Jeff' ? 'selected' : '' }}>Jeff</option>
Radio Button:
<input type="radio" name="gender" value="M" {{ old('name', $DB->default-value)== "M" ? 'checked' : '' }} />
Another way of doing it: write a small if statment to determine which value should be evaluated.
@php
if(old('name') !== null){
$option = old('name');
}
else{ $option = $database->value; }
@endphp
<select name="name">
<option value="Bob" {{ $option == 'Bob' ? selected : '' }}>Bob</option>
<option value="Jeff" {{ $option == 'Jeff' ? selected : '' }}>Jeff</option>
</select>
<input type="radio" name="gender" value="M" {{ $option == "M" ? 'checked' : '' }} />
<input type="radio" name="gender" value="F" {{ $option == "F" ? 'checked' : '' }} />
Setting old value of input with an array name e.g name="name[]":
<input type="text" name="name[]" value="{{ old('name.0) }}" />
This will give you the old value of the input with an index of 0
I have tested this and it works, I hope it helps someone.
回答3:
There is nothing wrong with the way you are doing things as Laravel gives multiple ways to handle the situation you're describing.
What I would suggest is using the Laravel Collective Form and HTML packages to build your form. This package will automatically handle binding old request values to your form if validation fails
https://laravelcollective.com/docs/5.2/html
回答4:
I solved that issue in my application if you want to get old previous inserted value in input you should try this one I did like this.
function SaveData(Request $request)
{
$sValidationRules = [
'firstname' => 'required',
'lastname' => 'required',
'email' => 'required',
'phone' => 'required',
];
$validator = Validator::make($request->all(), $sValidationRules);
if ($validator->fails()) // on validator found any error
{
// pass validator object in withErrors method & also withInput it should be null by default
return redirect('Your Route Hare')->withErrors($validator)->withInput();
}
Employee::create($request->all());
return redirect(' your route hare ');
}
& after then get old data in input field value like this using {{ Request::old('firstname') }} Happy Coding. :)
<input type="text" name="firstname" id="firstname" value="{{ Request::old('firstname') }}" class="form-control" placeholder="First Name">
回答5:
Another way to do that is get the data from the dog
class, like this:
value="{{old('title') ?? $dog->title }}"
Why? Because old()
is for validation; when you fail validation, the input will remain available in the field. In the case where validation hasn't fired yet, value
will be filled with $dog->title
.
来源:https://stackoverflow.com/questions/38461677/what-is-the-best-practice-to-show-old-value-when-editing-a-form-in-laravel