问题
I received this error when I run my code.
Error:
Warning: mysqli_real_escape_string() expects exactly 2 parameters, 1 given in C:\wamp\www\SearchEngine\search.php on line 11
Code:
<?php
//php code goes here
include 'connect.php'; // for database connection
include 'script_suggestion.php';
include 'script_close_suggestion_box.php';
$query = $_GET['q']; // query
$button = $_GET ['submit'];
if (isset($_GET['page'])) {
$page_number = (int)$_GET['page'];
$page_number = mysqli_real_escape_string($page_number);
}
else
$page_number = 1;
$results_per_page = 3;
?>
How can I solve this?
Thanks in advance.
回答1:
If you use procedural style
mysqli_real_escape_string ( mysqli $link , string $escapestr )
More: http://www.php.net/manual/en/mysqli.real-escape-string.php
回答2:
the syntax you wrote is for mysql_real_escape_string
.in mysqli_real_escape_string
u have to add link also. the correct syntax is:
string mysqli_real_escape_string ( mysqli $link , string $escapestr )
来源:https://stackoverflow.com/questions/20858035/mysqli-real-escape-string-expects-exactly-2-parameters-1-given