Why can't I validate a JComponent?

问题

From JavaDoc:

public void validate()

Validates this container and all of its subcomponents. Validating a container means laying out its subcomponents.

That is what I want to do. With an as lightweight component as possible. But when I do this whith a JComponent a call to validate() doesn't make the component "valid".

    JComponent c = new JComponent() {};
    System.out.println(c.isValid()); // false
    c.validate();
    System.out.println(c.isValid()); // false

Why can't I make a JComponent valid?

回答1:

In the docs for isValid() it says:

A component is valid when it is correctly sized and positioned within its parent container and all its children are also valid.

This is the case until you reach a Top-Level Container (JFrame, JInternalFrame or JApplet). In the example you have in your question, your JComponent doesn't have a parent so it can never be valid.

回答2:

The Javadoc for java.awt.Component.isValid() states:

A component is valid when it is correctly sized and positioned within its parent container and all its children are also valid.

In short, you can't validate the component until it has been added to a container.

回答3:

To add up to what has been said in the answers, don't forget to override getPreferedSize() method to return your component preferred size. Otherwise the layout manager won't position your JComponent hence will not be displayed.

来源：https://stackoverflow.com/questions/8362484/why-cant-i-validate-a-jcomponent

标签

java

swing

layout

jcomponent