How to parcel List<Int> with kotlin

半世苍凉 提交于 2019-12-20 02:34:43

问题


I want to pass a data class (that contains list of int as a property) to other activity through Bundle and therefore i need to add Parcelable implementation to my data class. any idea about how to parcel this property?

data class Test(val id: Long, val files: List<Int>?) : Parcelable {

constructor(parcel: Parcel) : this(
        parcel.readLong(),
        TODO("files"))

override fun writeToParcel(parcel: Parcel, flags: Int) {
    parcel.writeLong(id)
}

override fun describeContents(): Int {
    return 0
}

companion object CREATOR : Parcelable.Creator<Test> {
    override fun createFromParcel(parcel: Parcel): Test {
        return Test(parcel)
    }

    override fun newArray(size: Int): Array<Test?> {
        return arrayOfNulls(size)
    }
}

回答1:


You can write a list of integers as int[]:

parcel.writeIntArray(files.toIntArray())

Make sure you use the same data structure when reading back:

files = parcel.createIntArray().toList()

You could make it more efficient using extension functions by skipping the array representation:

parcel.writeIntList(files)
files = parcel.createIntList()

fun Parcel.writeIntList(input:List<Int>) {
    writeInt(input.size) // Save number of elements.
    input.forEach(this::writeInt) // Save each element.
}

fun Parcel.createIntList() : List<Int> {
    val size = readInt()
    val output = ArrayList<Int>(size)
    for (i in 0 until size) {
        output.add(readInt())
    }
    return output
}


来源:https://stackoverflow.com/questions/48371013/how-to-parcel-listint-with-kotlin

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