问题
I am trying to divide all the elements of a list filled with integers by another integer (functionality like in numpy arrays) by list comprehension, like so:
results = 300 * [0]
for i in range(100):
for j in range(300):
results[j] += random.randrange(0,300)
average_results = [results[x] / 100 for x in results]
However, if I run this in Python, it throws an
IndexError: list index out of range
I have worked around this by using a regular for loop:
average_results = []
for x in results:
average_results.append(x/100)
which works like a charm.
However, in my mind the two approaches should yield the same results, so I am totally stunted as to why it does not work.
Can someone point me in the right direction?
回答1:
The problem is with:
[results[x] / 100 for x in results]
Here you are iterating over values in the results list (for x in results
). And then for each of them trying to access the element with this index.
What you rather meant was:
[x / 100 for x in results]
In other words - the "for ... in ..." part of list comprehension works with values in the list, not their indices.
BTW, your [x / 100 for x in results]
won't give you an average of all values. It will "only" take each of them and divide by 100.
回答2:
This is the equivalent list comprehension to your loop:
average_results = [x / 100 for x in results]
x
is already the value form results
. Don't index again into it with results[x]
.
回答3:
Your array is filled with random integer values, ranging from 0 to 29999. In your list comprehension you make, as far as I can see, a mistake here:
results[x]
x
is already the value in the array, i.e. the random integer. You get the IndexError
because results[29999]
is, for example, one of the possible calls there.
What you want instead is to not use x
as an index:
average_results = [x / 100 for x in results]
回答4:
you can use one of these at the end:
1. average_results = [results[x] / 100 for x in range(len(results))]
2. average_results = [x / 100 for x in results]
the problem is you're trying to access to an index that does not exist (x is the value there not the index)
回答5:
This should be straight forward and possible.
In [1]: results = 10 * [10]
In [2]: [_/10 for _ in results]
Out[2]: [1, 1, 1, 1, 1, 1, 1, 1, 1, 1]
来源:https://stackoverflow.com/questions/47828209/divide-elements-of-a-list-by-integer-with-list-comprehension-index-out-of-range