问题
How Can I convert QString to decimal ?
In C# code it look like that:
public static decimal ConvertToDecimal(string tekst, bool upperOnly)
{
decimal num = 0m;
decimal num2 = 1m;
string text = upperOnly ? "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ" : "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ01234";
int i = tekst.Length - 1;
while (i >= 0)
{
num += text.IndexOf(tekst[i]) * num2;
i--;
num2 *= text.Length;
}
return num;
}
回答1:
As per documentation:
int QString::toInt(bool * ok = 0, int base = 10) const
Returns the
string
converted to anint
using base base, which is10
by default and must be between 2 and 36, or 0. Returns 0 if the conversion fails.If a conversion error occurs,
*ok
is set to false; otherwise*ok
is set to true.If base is 0, the C language convention is used: If the string begins with "0x", base 16 is used; if the
string
begins with "0", base 8 is used; otherwise, base 10 is used.The string conversion will always happen in the 'C' locale. For locale dependent conversion use
QLocale::toInt()
Example:
QString str = "FF";
bool ok;
int hex = str.toInt(&ok, 16); // hex == 255, ok == true
int dec = str.toInt(&ok, 10); // dec == 0, ok == false
Note that depending on your exact use case, you may wish to look into the following documentations as well:
long QString::toLong(bool * ok = 0, int base = 10) const
qlonglong QString::toLongLong(bool * ok = 0, int base = 10) const
double QString::toDouble(bool * ok = 0) const
float QString::toFloat(bool * ok = 0) const
来源:https://stackoverflow.com/questions/20729239/qt-c-convert-qstring-to-decimal