问题
I have the following function signature
int foo(void **)
and am trying to give it a pointer to a char
pointer, i.e. char **
. My compiler is complaining with the following warning
argument of type "char **" is incompatible with parameter of type "void **"
Is this to be expected? I know passing a char *
to a function expecting a void *
requires no explicit cast but is this true for pointers to pointers?
Note : this is explicitly a C
question. I would be interested if different C
versions treat this differently.
回答1:
Chapter 22: Pointers to Pointers:
One side point about pointers to pointers and memory allocation: although the
void *
type, as returned bymalloc
, is a "generic pointer," suitable for assigning to or from pointers of any type, the hypothetical typevoid **
is not a "generic pointer to pointer".
So, only void *
is a generic pointer. void **
is not generic pointer. Therefore the argument passed to your function must be of type void **
.
Also see C-FAQ:
There is no generic pointer-to-pointer type in C.
void *
acts as a generic pointer only because conversions (if necessary) are applied automatically when other pointer types are assigned to and fromvoid *
's; these conversions cannot be performed if an attempt is made to indirect upon avoid **
value which points at a pointer type other thanvoid *
. When you make use of avoid **
pointer value (for instance, when you use the*
operator to access thevoid *
value to which thevoid **
points), the compiler has no way of knowing whether thatvoid *
value was once converted from some other pointer type. It must assume that it is nothing more than avoid *
; it cannot perform any implicit conversions.In other words, any
void **
value you play with must be the address of an actualvoid *
value somewhere; casts like(void **)&dp
, though they may shut the compiler up, are nonportable (and may not even do what you want; see also question 13.9). If the pointer that thevoid **
points to is not avoid *
, and if it has a different size or representation than avoid *
, then the compiler isn't going to be able to access it correctly.
来源:https://stackoverflow.com/questions/25161649/explicit-cast-required-to-pointer-to-void-pointer