GraphQl variable using grapiql - variable is undefined

柔情痞子 提交于 2019-12-18 09:51:44

问题


I am using this endpoint:

 @PostMapping("graphql")
    public ResponseEntity<Object> getResource(@RequestBody Object query) { // String query
        ExecutionResult result;
        if (query instanceof String) {
            result = graphQL.execute(query.toString()); // if plain text
        } else{
            String queryString = ((HashMap) query).get("query").toString();
            Object variables = ((HashMap) query).get("variables");
            ExecutionInput input = ExecutionInput.newExecutionInput()
                    .query(queryString)
                    .variables((Map<String, Object>) variables) // "var1" -> "test1"
                    .build();

            result = graphQL.execute(input);
        }
        return new ResponseEntity<Object>(result, HttpStatus.OK);
    }

When i don't have variable it works fine:

query {
    getItem(dictionaryType: "test1") {
        code
        name
        description
    }
}

When i add variable it starts to fail, see here:

query {
    getItem(dictionaryType: $var1) {
        code
        name
        description
    }
}

In my schema i have defined the query section as followed:

type Query {
    getItem(dictionaryType: String): TestEntity
}

In java code:

@Value("classpath:test.graphqls")
private Resource schemaResource;
private GraphQL graphQL;

@PostConstruct
private void loadSchema() throws IOException {
        File schemaFile = schemaResource.getFile();
        TypeDefinitionRegistry registry = new SchemaParser().parse(schemaFile);
        RuntimeWiring wiring = buildWiring();
        GraphQLSchema schema = new SchemaGenerator().makeExecutableSchema(registry, wiring);
        graphQL = GraphQL.newGraphQL(schema).build();
}


private RuntimeWiring buildWiring() {
        initializeFetchers();
        return RuntimeWiring.newRuntimeWiring()
                .type("Query", typeWriting -> typeWriting
                        .dataFetcher("getItem", dictionaryItemFetcher)

                )
                .build();
}

private void initializeFetchers() {
        dictionaryItemFetcher = dataFetchingEnvironment ->
                dictionaryService.getDictionaryItemsFirstAsString(dataFetchingEnvironment.getArgument("dictionaryType"));
}

回答1:


Any variables used inside an operation must be declared as part of the operation definition, like this:

query OptionalButRecommendedQueryName ($var1: String) {
  getItem(dictionaryType: $var1) {
    code
    name
    description
  }
}

This allows GraphQL to validate your variables against the provided type, and also validate that the variables are being used in place of the right inputs.



来源:https://stackoverflow.com/questions/54293234/graphql-variable-using-grapiql-variable-is-undefined

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!