CompletableFuture allof(..).join() vs CompletableFuture.join()

最后都变了- 提交于 2019-12-18 07:19:27

问题


I am currently using CompletableFuture supplyAsync() method for submitting some tasks to common thread pool. Here is what code snippet looks like:

final List<CompletableFuture<List<Test>>> completableFutures = resolvers.stream()
        .map(resolver -> supplyAsync(() -> task.doWork()))
        .collect(toList());

CompletableFuture.allOf(completableFutures.toArray(new CompletableFuture[completableFutures.size()])).join();

final List<Test> tests = new ArrayList<>();
completableFutures.stream()
        .map(completableFuture -> completableFuture.getNow())
        .forEach(tests::addAll);

I would like to know how below differs from above code. I removed the parent completableFuture from below code, and added join() for each of the completableFuture instead of getNow():

final List<CompletableFuture<List<Test>>> completableFutures = resolvers.stream()
        .map(resolver -> supplyAsync(() -> task.doWork()))
        .collect(toList());

final List<Test> tests = new ArrayList<>();
completableFutures.stream()
        .map(completableFuture -> completableFuture.join())
        .forEach(tests::addAll);

I am using this in the spring service and there are issues with thread pool exhaustion. Any pointers is deeply appreciated.


回答1:


First of all, .getNow() does not work, as this method requires a fall-back value as argument for the case the future is not completed yet. Since you are assuming the future to be completed here, you should also use join().

Then, there is no difference regarding thread exhaustion as in either case, you are waiting for the completion of all jobs before proceeding, potentially blocking the current thread.

The only way to avoid that, is by refactoring the code to not expect a result synchronously, but rather schedule the subsequent processing action to do done, when all jobs have been completed. Then, using allOf becomes relevant:

final List<CompletableFuture<List<Test>>> completableFutures = resolvers.stream()
    .map(resolver -> supplyAsync(() -> task.doWork()))
    .collect(toList());

CompletableFuture.allOf(completableFutures.toArray(new CompletableFuture<?>[0]))
    .thenAccept(justVoid -> {
        // here, all jobs have been completed
        final List<Test> tests = completableFutures.stream()
            .flatMap(completableFuture -> completableFuture.join().stream())
            .collect(toList());
        // process the result here
    });

By the way, regarding the toArray method on collections, I recommended reading Arrays of Wisdom of the Ancients…



来源:https://stackoverflow.com/questions/52370888/completablefuture-allof-join-vs-completablefuture-join

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