问题
Perhaps easiest to explain with an example:
$ echo '\&|'
\&|
$ echo '\&|' | while read in; do echo "$in"; done
&|
It seems that the "read" command is interpreting the slashes in the input as escapes and is removing them. I need to process a file line by line without changing its contents and I'm not sure how to stop read from being smart here. Any ideas?
回答1:
Accrding to: http://www.vias.org/linux-knowhow/bbg_sect_08_02_01.html :
-r
If this option is given, backslash does not act as an escape character. The backslash is considered to be part of the line. In particular, a backslash-newline pair may not be used as a line continuation.
It works on my machine.
$ echo '\&|' | while read -r in; do echo "$in"; done
\&|
回答2:
Use read -r, as per http://www.ss64.com/bash/read.html:
-r
If this option is given, backslash does not act as an escape character.
来源：https://stackoverflow.com/questions/924388/sh-read-command-eats-slashes-in-input