问题
I have the following java code:
DocumentBuilder db=DocumentBuilderFactory.newInstance().newDocumentBuilder();
Document doc=db.parse(new File("/opt/myfile"));
And /opt/myfile
contains something like:
<?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE archive SYSTEM "../../schema/xml/schema.dtd"> ...
I get the following error:
java.io.FileNotFoundException: /../schema/xml/schema.dtd (No such file or directory)
This is a large java framework that consumes an XML file produced elsewhere. I think the relative path is the problem. I don't think it will be acceptable to change the cwd before the JVM starts (the path comes from a config file that is read by the JVM itself) and I have not found a way to change the cwd while the JVM is running. How do I parse this XML file with the appropriate DTD?
回答1:
You need to use a custom EntityResolver to tweak the path of the DTD so that it can be found. For example:
db.setEntityResolver(new EntityResolver() {
@Override
public InputSource resolveEntity(String publicId, String systemId)
throws SAXException, IOException {
if (systemId.contains("schema.dtd")) {
return new InputSource(new FileReader("/path/to/schema.dtd"));
} else {
return null;
}
}
});
If schema.dtd
is on your classpath, you can just use getResourceAsStream
to load it, without specifying the full path:
return new InputSource(Foo.class.getResourceAsStream("schema.dtd"));
回答2:
You can also ignore the DTD altogether: http://marcels-javanotes.blogspot.com/2005/11/parsing-xml-file-without-having-access.html
回答3:
I used the custom EntityResolver like the example above but it still searched the DTD file in another base directory. So I debuged it and then found out I need to change user.dir system property. So I added this line to my application initialization method and it works now.
System.setProperty("user.dir")
回答4:
Below code work for me, It ignore DTD
Imports:
import java.io.ByteArrayInputStream;
import java.io.File;
import java.io.IOException;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.w3c.dom.Document;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.EntityResolver;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;
Code :
File fileName = new File("XML File Path");
DocumentBuilderFactory documentBuilderFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder documentBuilder = documentBuilderFactory.newDocumentBuilder();
EntityResolver resolver = new EntityResolver () {
public InputSource resolveEntity (String publicId, String systemId) {
String empty = "";
ByteArrayInputStream bais = new ByteArrayInputStream(empty.getBytes());
System.out.println("resolveEntity:" + publicId + "|" + systemId);
return new InputSource(bais);
}
};
documentBuilder.setEntityResolver(resolver);
Document document = documentBuilder.parse(fileName);
来源:https://stackoverflow.com/questions/4726279/parsing-an-xml-file-with-a-dtd-schema-on-a-relative-path