问题
I'm using javascript and would like to take a URL string that I have and break it down into its components such as the host, path, and query arguments.
I need to do this in order to get to one of the query arguments, which is itself a URL and is thus encoded in the original URL string.
I feel like there should be an easy way to do this in Javascript. Perhaps something that looks like this:
var what_I_Want = url("http://www.domain.com?queryArg1=somequeryargument").getQueryArgumentValue("queryArg1");
回答1:
The parseUri function will do everything you need
Edit
Alternatively you can get the DOM to do the hard work for you and access properties on a newly created a
object for different parts of the URL.
回答2:
<script type="text/javascript" language="javascript">
newURL = window.location.protocol + "//" + window.location.host + "/" + window.location.pathname;
</script>
Hope this will help..
回答3:
In javascript you can do this by using split() for the params and using the location object for the protocol and domain -- like Carl suggested
Also you can use parseUri as Tak suggested
There is also a jQuery plugin which makes parsing easier if you are already using jQuery in your project: https://github.com/allmarkedup/jQuery-URL-Parser#readme
Example:
$.url('http://allmarkedup.com?sky=blue&grass=green').param('sky'); // returns 'blue'
回答4:
Probably not the greatest way of doing it but a simple method to get the query string in JavaScript would be to just use something along the lines of:
a = "http://www.domain.com?queryArg1=somequeryargument";
query = a.substring(a.indexOf('?')+1);
You could then split the query up based on the &'s and again on the = to get at whatever param you need.
Sorry if this ain't very helpful as its a bit of a low tech method :P
EDIT: Just wrote a quick little JavaScript object to get URL Query parameters for you (sort of like) in your example. Only tested it in chrome but in theory it should work :)
//Quick and dirty query Getter object.
function urlQueryGetter(url){
//array to store params
var qParam = new Array();
//function to get param
this.getParam = function(x){
return qParam[x];
}
//parse url
query = url.substring(url.indexOf('?')+1);
query_items = query.split('&');
for(i=0; i<query_items.length;i++){
s = query_items[i].split('=');
qParam[s[0]] = s[1];
}
}
//Useage
var bla = new urlQueryGetter("http://www.domain.com?queryArg1=somequeryargument&test=cheese");
alert(bla.getParam('test'));
来源:https://stackoverflow.com/questions/6560618/break-a-url-into-its-components