问题
The usual VB way to handle a computationally heavy task is to put it in a background worker thread, while the main thread keeps handling the UI.
Say for whatever reason I needed to do this the other way around: the main thread doing the grunt work and the background one updating the UI.
Here's what I have so far. The only problem is, while the UI window (Form1) does get redrawn, you can't interact with it, not even move or resize it (the mouse cursor turns to hourglass and won't click).
Public Class ProgressDisplay
Private trd As Thread
Public Sub New()
trd = New Thread(AddressOf threadtask)
trd.Start()
End Sub
Private Sub threadtask()
Dim f1 As Form1
f1 = New Form1
f1.Show()
Do
f1.Update()
Thread.Sleep(100)
Loop
End Sub
End Class
Edit: Ideally I need to present an interface like this to the client
Public Class ProgressDisplay
Public Sub New()
Public Sub Update(byval progress as int)
End Class
The client will call it like this (actually in unmanaged c++ over COM but you get the picture):
Dim prog = new ProgressDisplay()
DoLotsOfWork(addressof prog.update) ' DoLotsOfWork method takes a callback argument to keep client informed of progress
回答1:
To clearly restate the problem - you need to provide a visual component to a client who will use it within their own program. The client's program, outside of your control, ties up its main(ie:UI) thread and you are required to have your visual component continue working while the client's program is frozen.
You CAN do this, but this is probably not the most elegant or recommended solution. You need to create a second application context and a new message loop which can continue running beside the main UI thread. A class something like this would work :
Imports System.Threading
Public Class SecondUIClass
Private appCtx As ApplicationContext
Private formStep As Form
Private trd As Thread
Private pgBar As ProgressBar
Delegate Sub dlgStepIt()
Public Sub New()
trd = New Thread(AddressOf NewUIThread)
trd.SetApartmentState(ApartmentState.STA)
trd.IsBackground = True
trd.Start()
End Sub
Private Sub NewUIThread()
formStep = New Form()
pgBar = New ProgressBar()
formStep.Controls.Add(pgBar)
appCtx = New ApplicationContext(formStep)
Application.Run(appCtx)
End Sub
Public Sub StepTheBar()
formStep.Invoke(New dlgStepIt(AddressOf tStepIt))
End Sub
Private Sub tStepIt()
pgBar.PerformStep()
End Sub
End Class
Essentially what you are doing with the above class is creating a new application context within a new STA thread (giving that thread a message loop). That context contains a main form (giving the thread ownership of it and responsibility for its message processing) which can continue to operate aside from the main UI thread. This is much like having a program within a program - two UI threads, each with their own mutually exclusive set of controls.
Calls which interact with any of the controls owned by the new UI thread (or its form) must be marshalled with Control.Invoke
from the primary UI thread (or others) to ensure that your new UI thread is the one doing the interaction. You could also use BeginInvoke
here.
This class has NO cleanup code, no checks for safety, etc (be warned) and I'm not even sure it would finish up gracefully - I leave that task to you. This just illustrates a way to get started. In the main form you would do something like :
Public Class Form1
Private pgClass As New SecondUIClass
Private Sub Button1_Click(ByVal sender As System.Object, _
ByVal e As System.EventArgs) Handles Button1.Click
Dim i As Integer
For i = 1 To 10
System.Threading.Thread.Sleep(1000)
pgClass.StepTheBar()
Next
End Sub
End Class
Running the application above would create Form1
as well as a second form created by pgClass
. Clicking Button1
on Form1
would lock up Form1 while it went through its loop but the second form would still remain alive and responsive, updating its progress bar each time Form1
called .StepTheBar()
.
The best solution in this case, really, is to have the 'client' learn how to program properly and avoid being stuck in this conundrum in the first place. In the case where that is completely impossible and you MUST create for them a component whch will remain alive despite their poor code then the above approach is probably your only recourse.
回答2:
The UI can only be updated via the thread that created it. Any thread can make a request to invoke a method on the UI thread so that it can update the UI, by using the Control.Invoke
method, but that will just sit and wait until the UI thread is no longer busy. If the UI thread is busy, the UI cannot be updated by anything or anyone. The UI only gets updated when the main message loop (AKA Application.Run
) processes the window messages in the queue and acts upon them. If the UI thread is busy, stuck in a loop or waiting for a response from a server, it can't process those window messages (unless you call DoEvents
, which I definitely do not recommend, if at all possible). So, yes, while the UI is busy, it will be locked up. That's the whole reason why everyone suggests doing any hefty business logic in a separate thread. If that wasn't an issue, why would anyone bother making worker threads?
回答3:
The UI can't be updated from any other thread than the main event dispatching thread. So you are trying to do something that won't work.
来源:https://stackoverflow.com/questions/11155628/visual-basic-net-how-to-create-a-thread-to-update-the-ui