问题
I want support for drop-downs in the toolbar filter fields as Filter toolbar drop-down not working in jqgrid 4.6.0 version. But it is working in 3.8 .version
I have referred the link for 3.8.
Please help me to fix in 4.6.0 version.
jQuery(document).ready(function() {
var categories = ["All", "sport", "science"];
var categoriesStr = ":All;1:sport;2:science";
var subcategories = ["All", "football", "formel 1", "physics", "mathematics"];
var subcategoriesStr =":All;1:football;2:formel 1;3:physics;4:mathematics";
var mydata = [
{id:0, Name:"Lukas Podolski", Category:1, Subcategory:1},
{id:1, Name:"Michael Schumacher", Category:1, Subcategory:2},
{id:2, Name:"Albert Einstein", Category:2, Subcategory:3},
{id:3, Name:"Blaise Pascal", Category:2, Subcategory:4}
];
var grid = jQuery("#list").jqGrid({
data: mydata,
datatype: 'local',
colModel: [
{ name: 'Name', index: 'Name', width: 200},
{ name: 'Category', index: 'Category', width: 200, formatter:'select', stype: 'select',
sorttype: function(cell) {return categories[cell];},
edittype:'select', editoptions: { value: categoriesStr },
searchoptions:{ sopt:['eq'] }
},
{ name: 'Subcategory', index: 'Subcategory', width: 200, formatter:'select', stype: 'select',
sorttype: function(cell) {return categories[cell];},
edittype:'select', editoptions: { value: subcategoriesStr},
searchoptions:{ sopt:['eq'] }
}
],
sortname: 'Name',
viewrecords: true,
rownumbers: true,
sortorder: "desc",
ignoreCase: true,
pager: '#pager',
caption: "Setting filter in the filter toolbar"
}).jqGrid('navGrid','#pager', { edit: false, add: false, del: false, search: false, refresh:false });
grid.jqGrid('filterToolbar', {stringResult: true, searchOnEnter: true, defaultSearch : "cn", beforeSearch: function() {
//alert("verifying the data");
var postData = grid.jqGrid('getGridParam','postData');
// we use `stringResult: true` so decoding of the search parameters are a little complex
var searchData = jQuery.parseJSON(postData.filters);
for (var iRule=0; iRule<searchData.rules.length; iRule++) {
if (searchData.rules[iRule].field === "Name") {
var valueToSearch = searchData.rules[iRule].data;
if (valueToSearch.length != 5) {
alert ("The search string MUST de 5 charachters length!");
return true; // error
}
}
}
return false;
}});
});
I have attached 4.6.0 version screen shot.
回答1:
My demo, which you reference in your question, is really old. I created it for the answer.
I updated the demo the the following which uses jqGrid 4.6.0. It uses the following code
$(function () {
"use strict";
var mydata = [
{id: "10", Name: "Miroslav Klose", Category: "Sport", Subcategory: "Football"},
{id: "20", Name: "Michael Schumacher", Category: "Sport", Subcategory: "Formula 1"},
{id: "30", Name: "Albert Einstein", Category: "Science", Subcategory: "Physics"},
{id: "40", Name: "Blaise Pascal", Category: "Science", Subcategory: "Mathematics"}
],
$grid = $("#list"),
getUniqueNames = function (columnName) {
var texts = this.jqGrid("getCol", columnName), uniqueTexts = [],
textsLength = texts.length, text, textsMap = {}, i;
for (i = 0; i < textsLength; i++) {
text = texts[i];
if (text !== undefined && textsMap[text] === undefined) {
// to test whether the texts is unique we place it in the map.
textsMap[text] = true;
uniqueTexts.push(text);
}
}
return uniqueTexts;
},
buildSearchSelect = function (uniqueNames) {
var values = ":All";
$.each(uniqueNames, function () {
values += ";" + this + ":" + this;
});
return values;
},
setSearchSelect = function (columnName) {
this.jqGrid("setColProp", columnName, {
stype: "select",
searchoptions: {
value: buildSearchSelect(getUniqueNames.call(this, columnName)),
sopt: ["eq"]
}
});
};
$grid.jqGrid({
data: mydata,
datatype: "local",
colModel: [
{name: "Name"},
{name: "Category"},
{name: "Subcategory"}
],
cmTemplate: {width: 200},
gridview: true,
autoencode: true,
sortname: "Name",
viewrecords: true,
rownumbers: true,
sortorder: "desc",
ignoreCase: true,
pager: "#pager",
height: "auto",
caption: "How to use filterToolbar better locally"
}).jqGrid("navGrid", "#pager",
{edit: false, add: false, del: false, search: false, refresh: false});
setSearchSelect.call($grid, "Category");
setSearchSelect.call($grid, "Subcategory");
$grid.jqGrid("setColProp", "Name", {
searchoptions: {
sopt: ["cn"],
dataInit: function (elem) {
$(elem).autocomplete({
source: getUniqueNames.call($(this), "Name"),
delay: 0,
minLength: 0,
select: function (event, ui) {
var $myGrid, grid;
$(elem).val(ui.item.value);
if (typeof elem.id === "string" && elem.id.substr(0, 3) === "gs_") {
$myGrid = $(elem).closest("div.ui-jqgrid-hdiv").next("div.ui-jqgrid-bdiv").find("table.ui-jqgrid-btable").first();
if ($myGrid.length > 0) {
grid = $myGrid[0];
if ($.isFunction(grid.triggerToolbar)) {
grid.triggerToolbar();
}
}
} else {
// to refresh the filter
$(elem).trigger("change");
}
}
});
}
}
});
$grid.jqGrid("filterToolbar",
{stringResult: true, searchOnEnter: true, defaultSearch: "cn"});
});
来源:https://stackoverflow.com/questions/29140997/drop-down-not-working-in-filter-toolbar-for-jqgrid-4-6-0-version