How to search JSON array in MySQL?

问题

Let's say I have a JSON column named data in some MySQL table, and this column is a single array. So, for example, data may contain:

[1,2,3,4,5]

Now I want to select all rows which have a data column where one of its array elements is greater than 2. Is this possible?

I tried the following, but seems it is always true regardless of the values in the array:

SELECT * from my_table
WHERE JSON_EXTRACT(data, '$[*]') > 2;

回答1:

SELECT JSON_SEARCH('["1","2","3","4","5"]', 'one', "2") is not null

is true

SELECT JSON_SEARCH('["1","2","3","4","5"]', 'one', "6") is not null

is false

回答2:

A possible way is to deal with the problem as string matching. Convert the JSON to string and match.

Or you can use JSON_CONTAINS.

回答3:

I don't know if we found the solution. I found with MariaDB a way, to search path in a array. For example, in array [{"id":1}, {"id":2}], I want find path with id equal to 2.

SELECT JSON_SEARCH('name_field', 'one', 2, null, '$[*].id')
FROM name_table

The result is:

"$[1].id"

The asterisk indicate searching the entire array

回答4:

Since MySQL 8 there is a new function called JSON_TABLE.

CREATE TABLE my_table (id INT, data JSON);

INSERT INTO my_table VALUES 
  (1, "[1,2,3,4,5]"), 
  (2, "[0,1,2]"), 
  (3, "[3,4,-10]"), 
  (4, "[-1,-2,0]");

SELECT DISTINCT my_table.* 
FROM my_table, JSON_TABLE(data, "$[*]" COLUMNS(nr INT PATH '$')) as ids 
WHERE ids.nr > 2;

+------+-----------------+
| id   | data            |
+------+-----------------+
|    1 | [1, 2, 3, 4, 5] |
|    3 | [3, 4, -10]     |
+------+-----------------+
2 rows in set (0.00 sec)

回答5:

You can use JSON extract to search and select data

SELECT data, data->"$.id" as selectdata
FROM table
WHERE JSON_EXTRACT(data, "$.id") = '123'
#ORDER BY c->"$.name";
limit 10 ;

回答6:

SET @doc = '[{"SongLabels": [{"SongLabelId": "111", "SongLabelName": "Funk"}, {"SongLabelId": "222", "SongLabelName": "RnB"}], "SongLabelCategoryId": "test11", "SongLabelCategoryName": "曲风"}]';
SELECT *,  JSON_SEARCH(@doc, 'one', '%un%', null, '$[*].SongLabels[*].SongLabelName')FROM t_music_song_label_relation;

result: "$[0].SongLabels[0].SongLabelName"

SELECT song_label_content->'$[*].SongLabels[*].SongLabelName' FROM t_music_song_label_relation;

result: ["Funk", "RnB"]

来源：https://stackoverflow.com/questions/36249828/how-to-search-json-array-in-mysql

标签

mysql

mysql-json