Add php variable inside echo statement as href link address?

问题

I'm trying to use a php variable to add a href value for a link in an echo statement.

Here's a simplified version of the code I want to use. I know that I can't just add the variable into the echo statement, but I can't seem to find an example anywhere that works.

$link_address = '#';
echo '<a href="$link_address">Link</a>';

Any pointers appreciated.

回答1:

Try like

HTML in PHP :

echo "<a href='".$link_address."'>Link</a>";

Or even you can try like

echo "<a href='$link_address'>Link</a>";

Or you can use PHP in HTML like

PHP in HTML :

<a href="<?php echo $link_address;?>"> Link </a>

回答2:

you can either use

echo '<a href="'.$link_address.'">Link</a>';

or

echo "<a href=\"$link_address\">Link</a>';

if you use double quotes you can insert the variable into the string and it will be parsed.

回答3:

Basically like this,

<?php $link = ""; // Link goes here! print "<a href="'.$link.'">Link</a>"; ?>

回答4:

as simple as that: echo '<a href="'.$link_address.'">Link</a>';

回答5:

If you want to print in the tabular form with, then you can use this:

echo "<tr> <td><h3> ".$cat['id']."</h3></td><td><h3> ".$cat['title']."<h3></</td><td> <h3>".$cat['desc']."</h3></td><td><h3> ".$cat['process']."%"."<a href='taskUpdate.php' >Update</a>"."</h3></td></tr>" ;

来源：https://stackoverflow.com/questions/18916966/add-php-variable-inside-echo-statement-as-href-link-address