问题
I need to convert dates into Excel serial numbers for a data munging script I am writing. By playing with dates in my OpenOffice Calc workbook, I was able to deduce that '1-Jan 1899 00:00:00' maps to the number zero.
I wrote the following function to convert from a python datetime object into an Excel serial number:
def excel_date(date1):
temp=dt.datetime.strptime('18990101', '%Y%m%d')
delta=date1-temp
total_seconds = delta.days * 86400 + delta.seconds
return total_seconds
However, when I try some sample dates, the numbers are different from those I get when I format the date as a number in Excel (well OpenOffice Calc). For example, testing '2009-03-20' gives 3478032000 in Python, whilst excel renders the serial number as 39892.
What is wrong with the formula above?
*Note: I am using Python 2.6.3, so do not have access to datetime.total_seconds()
回答1:
It appears that the Excel "serial date" format is actually the number of days since 1900-01-00, with a fractional component that's a fraction of a day, based on http://www.cpearson.com/excel/datetime.htm. (I guess that date should actually be considered 1899-12-31, since there's no such thing as a 0th day of a month)
So, it seems like it should be:
def excel_date(date1):
temp = dt.datetime(1899, 12, 30) # Note, not 31st Dec but 30th!
delta = date1 - temp
return float(delta.days) + (float(delta.seconds) / 86400)
回答2:
While this is not exactly relevant to the excel serial date format, this was the top hit for exporting python date time to Excel. What I have found particularly useful and simple is to just export using strftime.
import datetime
current_datetime = datetime.datetime.now()
current_datetime.strftime('%x %X')
This will output in the following format '06/25/14 09:59:29' which is accepted by Excel as a valid date/time and allows for sorting in Excel.
回答3:
if the problem is that we want DATEVALUE() excel serial number for dates, the toordinal() function can be used. Python serial numbers start from Jan1 of year 1 whereas excel starts from 1 Jan 1900 so apply an offset. Also see excel 1900 leap year bug (https://support.microsoft.com/en-us/help/214326/excel-incorrectly-assumes-that-the-year-1900-is-a-leap-year)
def convert_date_to_excel_ordinal(day, month, year) :
offset = 693594
current = date(year,month,day)
n = current.toordinal()
return (n - offset)
回答4:
With the 3rd party xlrd.xldate module, you can supply a tuple structured as (year, month, day, hour, minute, second)
and, if necessary, calculate a day fraction from any microseconds component:
from datetime import datetime
from xlrd import xldate
from operator import attrgetter
def excel_date(input_date):
components = ('year', 'month', 'day', 'hour', 'minute', 'second')
frac = input_date.microsecond / (86400 * 10**6) # divide by microseconds in one day
return xldate.xldate_from_datetime_tuple(attrgetter(*components)(input_date), 0) + frac
res = excel_date(datetime(1900, 3, 1, 12, 0, 0, 5*10**5))
# 61.50000578703704
来源:https://stackoverflow.com/questions/9574793/how-to-convert-a-python-datetime-datetime-to-excel-serial-date-number