问题
I have a (maybe) silly question.
My data: File 1
1234.34 a 1235.34 d
3456.23 b 3457.23 e
2325.89 c 2327.89 f
I want something like
awk '{if($1==$3) print $4}'
But of course if I do this, it will print nothing. So I want to modify the "precision" of $3 (in this case)
in the sense that when awk read $3 it finds this:
124
345
232
then it must be a way to do this, but I don't know it.
awk '{if($1==(three digits precision $3)) print $4}'
Help?
回答1:
You could calculate the difference of the two values:
awk '$1 - $3 < 0.01 || $3 - $1 < 0.01 {print $4}' file
来源:https://stackoverflow.com/questions/22934069/awk-length-of-column-number