问题
So I had some shared_mutex and done this:
boost::upgrade_lock<boost::shared_mutex> lock(f->mutex);
boost::upgrade_to_unique_lock<boost::shared_mutex> uniqueLock(lock);
now I want to "unlock it" or at least downgrade it to something like:
boost::shared_lock<boost::shared_mutex> lock_r(f->mutex);
How to do such thing? Is it possible?
回答1:
If you let the upgrade_to_unique_lock
go out of scope, it will automatically downgrade back to upgrade ownership.
For example
void foo() {
boost::upgrade_lock<boost::shared_mutex> lock(f->mutex);
// Do shared operations, as mutex is held upgradeable
// ...
if(need_to_get_unique)
{
boost::upgrade_to_unique_lock<boost::shared_mutex> uniqueLock(lock);
// Do exclusive operations, as mutex is held uniquely
// ...
// At end of scope unique is released back to upgradeable
}
// Only shared operations here, as it's only held upgradeable
// ...
// At end of scope mutex is completely released
}
Edit: One other thing. If a given function only requires exclusive locks, you can use boost::unique_lock
and lock uniquely, without going through both the upgrade
and upgrade_to_unique
locks.
来源:https://stackoverflow.com/questions/7704870/how-to-unlock-boostupgrade-to-unique-lock-made-from-boostshared-mutex