How to construct a TransformManyBlock with a delegate

怎甘沉沦 提交于 2019-12-13 13:20:10

问题


I'm new to C# TPL and DataFlow and I'm struggling to work out how to implement the TPL DataFlow TransformManyBlock. I'm translating some other code into DataFlow. My (simplified) original code was something like this:

private IEnumerable<byte[]> ExtractFromByteStream(Byte[] byteStream)
{
    yield return byteStream; // Plus operations on the array
}

And in another method I would call it like this:

foreach (byte[] myByteArray in ExtractFromByteStream(byteStream))
{
    // Do stuff with myByteArray
}

I'm trying to create a TransformManyBlock to produce multiple little arrays (actually data packets) that come from the larger input array (actually a binary stream), so both in and out are of type byte[].

I tried what I've put below but I know I've got it wrong. I want to construct this block using the same function as before and to just wrap the TransformManyBlock around it. I got an error "The call is ambiguous..."

var streamTransformManyBlock = new TransformManyBlock<byte[], byte[]>(ExtractFromByteStream);

回答1:


The compiler has troubles with inferring the types. You need to either specify the delegate type explicitly to disambiguate the call:

var block = new TransformManyBlock<byte[], byte[]>(
    (Func<byte[], IEnumerable<byte[]>>) ExtractFromByteStream);

Or you can use a lambda expression that calls into that method:

var block = new TransformManyBlock<byte[], byte[]>(
    bytes => ExtractFromByteStream(bytes));


来源:https://stackoverflow.com/questions/33608678/how-to-construct-a-transformmanyblock-with-a-delegate

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!