问题
I have developed a mysql database and a php code. In php code i am using jQuery (ajax call) to fetch the data from the database. In html file i have printed datatable's table head only. Rest data i want to fetch from the database. code is given:
HTML CODE:
<div class="container box">
<div class="table-responsive">
<div id="alert_message"></div>
<table id="example" class="display">
<thead>
<tr>
<th>Student ID</th>
<th>Student Name</th>
<th>Email ID</th>
<th>Mobile</th>
<th>Status</th>
</tr>
</thead>
</table>
</div>
</div>
jQuery CODE:
<script>
$(document).ready(function() {
$('#example').dataTable({
"processing": true,
"serverSide": true,
"ajax": {
"url": "fetch.php",
"type": "GET",
"datatype": "json"
}
});
});
</script>
fetch.php
<?php
$connect = mysqli_connect("localhost","root","","lib");
$sql = "SELECT StudentId, FullName, EmailId, MobileNumber, Status FROM tblstudents";
$result = mysqli_query($connect,$sql);
$json_array = array();
while ($row = mysqli_fetch_assoc($result))
{
$json_array[] = $row;
}
echo json_encode($json_array);
?>
Still the data is not printed in the datatable. What changes are necessary in jQuery?
回答1:
In jQuery Datatables, not only you can fetch data from ajax call. you can manage page ordering, searching as well.
first of all you have to modify your javascript like this.
$(document).ready(function() {
$('#example').dataTable({
"bProcessing": true,
"serverSide": true,
"ajax": {
"url": "fetch.php",
"type": "post"
},
error: function () { // error handling code
$("#example").css("display", "none");
}
});
});
Then as you can see in the browsers Developer Tools -> Network tap, all the parameters that wanted for searching, sorting and ordering will be pass trough the ajax call.
you can see it by print_r($_POST) in the ajax page (in your case fetch.php) and viewing it on ajax respond in the browsers Developer Tools -> Network tap.
you can collect all of that as follows,
$order_by = $_POST['order']; // This array contains order information of clicked column
$search = $_POST['search']['value']; // This array contains search value information datatable
$start = $_POST['start']; // start limit of data
$length = $_POST['length']; // end limit of data
$order_type = $order_by[0]['dir'];
if ($order_by[0]['column']==0){
$order_column = "table_column_name_of_the_first_column_in_the_datatable";
} elseif ($order_by[0]['column']==1){
$order_column = "table_column_name_of_the_second_column_in_the_datatable";
}
then you can construct the query as follows,
if ($search!='' || $search!=NULL) {
$str = "WHERE column_name_to_search LIKE '%$search%' OR column_name_to_search LIKE '%$search%' ";
} else {
$str = "";
}
$data[][] = array();
$i = 0;
$sql = $connection->query("SELECT * FROM your_table $str ORDER BY $order_column $order_type LIMIT $start,$length");
while ($row_1 = $sql->fetch_assoc()){
$data[$i] = array($row_1['column_1'],$row_1['column_2']);
$i++;
}
then to get total record count you can do as follows,
$sql_2 = $connection->query("SELECT COUNT(*) AS all_count FROM your_table $str");
$row_2 = $sql_2->fetch_assoc();
$totalRecords = $row_2['all_count'];
if ($totalRecords==0){
$data = array();
}
finally construct the json out put that will be sent to the front view.
$json_data = array(
"draw" => intval( $_POST['draw'] ),
"recordsTotal" => intval( $totalRecords ),
"recordsFiltered" => intval($totalRecords),
"data" => $data // total data array
);
$json_data = json_encode($json_data);
echo $json_data;
That will work.
回答2:
I know this is really late, but I used the exact same code as you (thanks for that by the way!), and what made it work for me is to simply add to the JQuery code:
dataSrc = '' (after url = '...')
so that DataTables knows that it's loading an array. Putting that in made the code work fine!
来源:https://stackoverflow.com/questions/51722356/fetch-data-from-mysql-database-into-datatable-using-jquery