context.openFileInput() returning null when trying to access a stored file

问题

Currently, I have the following code for saving a Web Archive and then getting it as a FileInputStream. However, the channel within webContent remains null and a FileNotFoundException is thrown:

        // Save the Web Archive once loading is finished
        String path = context.getFilesDir().getAbsolutePath()
                + File.separator + WEB_PREFIX + postId;
        webView.saveWebArchive(path);
        FileInputStream webContent = null;
        try {
            webContent = context.openFileInput(WEB_PREFIX + postId);
        } catch (FileNotFoundException e) {
            Log.d("onPageFinished()", "FileNotFoundException");
            e.printStackTrace();
        }

If I try to perform context.openFileInput(path) instead, I get

09-05 23:39:42.448: E/AndroidRuntime(8399): java.lang.IllegalArgumentException: File /data/data/com.example/files/web-2189241737372651547 contains a path separator

Does anyone know of a solution? The file certainly exists, since I saved it in the previous line.

回答1:

openFileInput() doesn't accept paths, only a file name if you want to access a path.

Use this instead:

File file = new File(this.getFilesDir().getAbsolutePath() + (WEB_PREFIX + postId));

EDIT: You need to make sure you are saving and retrieving the file from the same place. Give this a go:

Note: I'm not sure you need File.separator but try with and without it and see which one works.

 String path = context.getFilesDir().getAbsolutePath()
                + File.separator + WEB_PREFIX + postId;
        webView.saveWebArchive(path);
        FileInputStream webContent = null;
        try {
            webContent = new File(path);
        } catch (FileNotFoundException e) {
            Log.d("onPageFinished()", "FileNotFoundException");
            e.printStackTrace();
        }

来源：https://stackoverflow.com/questions/18649543/context-openfileinput-returning-null-when-trying-to-access-a-stored-file

标签

android

android-file