问题
Is there any difference between the following two statement? They both work.
if ( ((Func<bool>)(()=>true))() ) { .... };
if ( new Func<bool>(()=>true)()) { .... };
回答1:
No, they both compile to exactly the same IL.
It's easier to see if you actually give the lambda body something that depends on state - otherwise the compiler caches a single delegate instance for each lambda. But for example:
using System;
class Test
{
bool value = DateTime.Now.Hour == 10;
void Cast()
{
if (((Func<bool>)(() => value))())
{
Console.WriteLine("Yes");
}
}
void New()
{
if (new Func<bool>(() => value)())
{
Console.WriteLine("Yes");
}
}
static void Main()
{
new Test().Cast();
new Test().New();
}
}
Now the IL for Cast
is:
.method private hidebysig instance void Cast() cil managed
{
// Code size 39 (0x27)
.maxstack 2
.locals init (bool V_0)
IL_0000: nop
IL_0001: ldarg.0
IL_0002: ldftn instance bool Test::'<Cast>b__0'()
IL_0008: newobj instance void class [mscorlib]System.Func`1<bool>::.ctor(object,
native int)
IL_000d: callvirt instance !0 class [mscorlib]System.Func`1<bool>::Invoke()
IL_0012: ldc.i4.0
IL_0013: ceq
IL_0015: stloc.0
IL_0016: ldloc.0
IL_0017: brtrue.s IL_0026
IL_0019: nop
IL_001a: ldstr "Yes"
IL_001f: call void [mscorlib]System.Console::WriteLine(string)
IL_0024: nop
IL_0025: nop
IL_0026: ret
} // end of method Test::Cast
and the IL for New
is:
.method private hidebysig instance void New() cil managed
{
// Code size 39 (0x27)
.maxstack 2
.locals init (bool V_0)
IL_0000: nop
IL_0001: ldarg.0
IL_0002: ldftn instance bool Test::'<New>b__1'()
IL_0008: newobj instance void class [mscorlib]System.Func`1<bool>::.ctor(object,
native int)
IL_000d: callvirt instance !0 class [mscorlib]System.Func`1<bool>::Invoke()
IL_0012: ldc.i4.0
IL_0013: ceq
IL_0015: stloc.0
IL_0016: ldloc.0
IL_0017: brtrue.s IL_0026
IL_0019: nop
IL_001a: ldstr "Yes"
IL_001f: call void [mscorlib]System.Console::WriteLine(string)
IL_0024: nop
IL_0025: nop
IL_0026: ret
} // end of method Test::New
As you can see, they're same apart from the ldftn
call, which just uses the appropriate compiler-generated method.
来源:https://stackoverflow.com/questions/24705925/cast-to-func-vs-new-func