问题
I am working on an application that needs to obtain a random picture from the android device's built-in picture gallery and then display it on the screen. Here's what I have to work with:
-An ImageView object called picture -The ID, TITLE, DATA, MIME_TYPE, and SIZE of the picture I want to display
I think the problem is I don't know what information I need to put in this line:
picture.setImageResource(???);
Here's all my code to give you some idea of what I'm trying to do:
public void generateImage() {
// Get list of images accessible by cursor
ContentResolver cr = getActivity().getContentResolver();
String[] columns = new String[] {
ImageColumns._ID,
ImageColumns.TITLE,
ImageColumns.DATA,
ImageColumns.MIME_TYPE,
ImageColumns.SIZE };
Cursor cursor = cr.query(MediaStore.Images.Media.EXTERNAL_CONTENT_URI,
columns, null, null, null);
// Collect Picture IDs
cursor.moveToFirst();
ArrayList<Integer> picList = new ArrayList<Integer>();
while (!cursor.isAfterLast()) {
picList.add(cursor.getInt(0));
cursor.moveToNext();
}// end for
// Generate random number
int imageCount = picList.size() - 1;
Log.d("NUMBER OF IMAGES", "Image Count = " + imageCount);
Random random = new Random();
int randomInt = random.nextInt(imageCount);
// Extract the image
int picID = picList.get(randomInt);
picture.setImageResource(picID);
}// end Generate Image
Anybody have any idea what I need to do in order to set the picture object to the picture that I have from the gallery (preferably using the information I've already obtained)?
回答1:
Looks like you are saving an array of the cursor position... that would probably not give you much to work with. I think you'd rather populate an ArrayList with ImageColumns._ID and then use that string as a URI to open the image.
回答2:
//Extracting the image
columnIndex = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
cursor.moveToPosition(randomInt);
filePath = cursor.getString(columnIndex);
imageView.setImageBitmap(decodeSampledBitmapFromResource(filePath,width,height));
And for efficiently using bitmaps so that you do not run into OutOfMemory Exceptions here are two functions startight from the androids developers page [link http://developer.android.com/training/displaying-bitmaps/load-bitmap.html]
public Bitmap decodeSampledBitmapFromResource(String path, int reqWidth, int reqHeight) {
// First decode with inJustDecodeBounds = true to check dimensions
final BitmapFactory.Options options = new BitmapFactory.Options();
options.inJustDecodeBounds = true;
BitmapFactory.decodeFile(path,options);
// Calculate inSampleSize
options.inSampleSize = calculateInSampleSize(options, reqWidth, reqHeight);
// Decode bitmap with inSampleSize set
options.inJustDecodeBounds = false;
return BitmapFactory.decodeFile(path, options);
}
public static int calculateInSampleSize( BitmapFactory.Options options, int reqWidth, int reqHeight) {
// Raw height and width of image
final int height = options.outHeight;
final int width = options.outWidth;
int inSampleSize = 1;
if (height > reqHeight || width > reqWidth) {
// Calculate ratios of height and width to requested height and width
final int heightRatio = Math.round((float) height / (float) reqHeight);
final int widthRatio = Math.round((float) width / (float) reqWidth);
// Choose the smallest ratio as inSampleSize value, this will guarantee
// a final image with both dimensions larger than or equal to the
// requested height and width.
inSampleSize = heightRatio < widthRatio ? heightRatio : widthRatio;
}
return inSampleSize;
}
来源:https://stackoverflow.com/questions/13612376/change-image-to-a-picture-in-gallery