Specify the specific heat of a material with Revit 2017 Python API

问题

With Revit 2017 Python API, I am trying to create new materials, and then assembling some of these to create new type of walls. It goes pretty well for all properties, except for the specific heat!

Basically, what I do is:

1. create a thermalAsset:

   themalA = ThermalAsset('Test', ThermalMaterialType.Solid)
   

2. Set the different thermal properties for that thermal asset (dummy values):

   thermalA.ThermalConductivity = 0.01
   
   thermalA.SpecificHeat = 0.001
   
   thermalA.Density = 1000.0
   

3. Then I create a PropertySetElement with that thermal asset:

   pse = PropertySetElement.Create(doc, thermalA)
   

4. Then I assign it to my material (that I previously created):

   mat.SetMaterialAspectByPropertySet(MaterialAspect.Thermal, pse)
   

Afetr that, I take a look in my materials list in Revit, and look at the thermal properties. Everything seems ok, except the Specific Heat, which remains at 0.0239 btu/(lb. F), whatever the value I input when I assign the specific heat. Density is ok, thermal conductivity is ok, but not specific heat.

I got no error message.

What am I missing?

Thanks a lot for any help.

Arnaud.

回答1:

Is the value you specify in the expected unit? Feet per Kelvin, squared-second. Cf., http://thebuildingcoder.typepad.com/blog/2013/04/whats-new-in-the-revit-2014-api.html > ThermalAsset.SpecificHeat.

I submitted this to the development team for further analysis as issue REVIT-111206 [API: setting ThermalAsset SpecificHeat fails]. Can you please provide a full reproducible case for them to test, e.g., a minimal RVT model with an embedded macro to run, cf., http://thebuildingcoder.typepad.com/blog/about-the-author.html#1b? Thank you!

来源：https://stackoverflow.com/questions/43188885/specify-the-specific-heat-of-a-material-with-revit-2017-python-api