问题
I have a MySql db with innoDB tables. Very simplified this is how two tables are layed out:
Table A:
- controlID(PK)
- controlText
Table B:
- controlOptionID(pk)
- controlID(FK to table A)
- controlOptionType
- controlOptionValue
So many controlOptions(table B) can reference one control(giving that control multiple options). But for each option two rows are made in table B: one row with controlOptionType = "linkToCreator" and controlOptionValue = (an ID to the template it was made from*). And the other row type = "optionSelected" and value = "true"(or false).
- = its a pretty complicated setup, but basically instead of set columns we are making dynamic ones by means of the type being what the column would have been called. So I couldnt link to the template with FK.
So now I need to select every control(which will have 2 controlOptions linking to it) where the one controlOptionValue value is true or false(depending on what i need) and the other controlOptionValue is an text ID that I specify.
What I think is the best way to do it is a
SELECT * FROM tableB WHERE controlOptionType = 'linkToCreator'
Then do a loop over that result set saying:
SELECT * FROM tableB WHERE tableB.controlID = (the controlID in this iterations row) AND tableB.controlValue = 'true'
But maybe thatls really inefficient, and either way I have no clue how to do that. It would be great if I could get a single query(i.e. not using stored procedures) that I specified templateID and true or false and it gave me a row result if it didn't find anything.
BTW this is for a search in our application with will need to go through TONS of rows so performance is paramount. And yes, I know the setup isnt the greatest...
Thanks :D
回答1:
Like this?
SELECT * FROM tableA AS A
LEFT JOIN tableB AS ctrl1 ON (A.controlID = ctrl1.controlID AND ctrl1.controlOptionType = ? AND ctrl1.controlOptionValue = ?)
LEFT JOIN tableB AS ctrl2 ON (A.controlID = ctrl2.controlID AND ctrl2.controlOptionType = ? AND ctrl2.controlOptionValue = ?)
回答2:
Try this:
SELECT *
FROM Table_A
LEFT JOIN Table_B
ON Table_A.ControlID = Table_B.ControlID
WHERE Table_A.controlOptionType = 'linkToCreator
来源:https://stackoverflow.com/questions/3339477/loop-in-mysql-or-alternative