问题
I have a distributed system where In one place i insert around 10000 items in a redis list then Call my multiple applications hook to process items. what i need is to Have some ListLeftPop type of methhod with numbers of items. It should remove items from the redis List and return to my calling application.
I am using Stackexchange.Resis.extension
My current method just for get (not pop) is
public static List<T> GetListItemRange<T>(string key, int start, int chunksize) where T : class
{
List<T> obj = default(List<T>);
try
{
if (Muxer != null && Muxer.IsConnected && Muxer.GetDatabase() != null)
{
var cacheClient = new StackExchangeRedisCacheClient(Muxer, new NewtonsoftSerializer());
var redisValues = cacheClient.Database.ListRange(key, start, (start + chunksize - 1));
if (redisValues.Length > 0)
{
obj = Array.ConvertAll(redisValues, value => JsonConvert.DeserializeObject<T>(value)).ToList();
}
}
}
catch (Exception ex)
{
Logger.Fatal(ex.Message, ex);
}
return obj;
}
For Pop and get i have find a snippet
var cacheClient = new StackExchangeRedisCacheClient(Muxer, new NewtonsoftSerializer());
var redisValues = cacheClient.ListGetFromRight<T>(key);
But it will only do for single item
回答1:
I assume that you are working on a queue, where you insert 1000 items at a single place and retrieve them at multiple place in the order at which it is inserted.
You can't achieve it with a single command but you can do it with 2 commands. You can write a lua script to make them atomic.
Lrange : http://redis.io/commands/lrange
Lrange list -100 -1
This will list you first 100 elements in the list. here the offset is -100. Note that this will return the items in the opposite order at which it is inserted. So you need to reverse the loop to ensure the queue mechanism.
Ltrim : http://redis.io/commands/ltrim
ltrim list 0 -101
This will trim the 1st 100 elements in the list. here 101 is n+1 so it must be 101. Here offset is 101
Writing them inside a lua block will ensure you the atomicity.
Let me give you a simple example.
You insert 100 elements in a single place.
lpush list 1 2 3 .. 100
You have multiple clients each trying to access this lua block. Say your n value is 5 here. 1st client gets in and gets first 5 elements inserted.
127.0.0.1:6379> lrange list -5 -1
1) "5"
2) "4"
3) "3"
4) "2"
5) "1"
You keep them in your lua object and delete them.
127.0.0.1:6379> LTRIM list 0 -6
OK
return them to your code, now the result you want is 1 2 3 4 5 but what you have got is 5 4 3 2 1. So you need to reverse the loop and perform the operation.
When the next client comes in it will get the next set of values.
127.0.0.1:6379> lrange list -5 -1
1) "10"
2) "9"
3) "8"
4) "7"
5) "6"
In this way you can achieve your requirement. Hope this helps.
EDIT:
Lua script:
local result = redis.call('lrange', 'list','-5','-1')
redis.call('ltrim','list','0','-6')
return result
回答2:
Thanks Karthikeyan. My C# code with redis is as following
public static RedisResult PopListItemRange(int chunksize, string key)
{
RedisResult valreturn = null;
try
{
IDatabase db;
if (Muxer != null && Muxer.IsConnected && (db = Muxer.GetDatabase()) != null)
{
valreturn = db.ScriptEvaluate(@" local result = redis.call('lrange',KEYS[1],ARGV[1], '-1')
redis.call('ltrim',KEYS[1],'0',ARGV[2])
return result", new RedisKey[] { key }, flags: CommandFlags.HighPriority, values: new RedisValue[] { -chunksize, -chunksize - 1 });
}
}
catch (Exception ex)
{
Logger.Fatal(ex.Message, ex);
}
return valreturn;
}
Now just doing a tweak that when the list is empty remove the redis Key
来源:https://stackoverflow.com/questions/37781806/redis-pop-list-item-by-numbers-of-items