Create a SQL query to retrieve most recent records

左心房为你撑大大i 提交于 2019-11-27 03:11:57
cmsjr

Aggregate in a subquery derived table and then join to it.

 Select Date, User, Status, Notes 
    from [SOMETABLE]
    inner join 
    (
        Select max(Date) as LatestDate, [User]
        from [SOMETABLE]
        Group by User
    ) SubMax 
    on [SOMETABLE].Date = SubMax.LatestDate
    and [SOMETABLE].User = SubMax.User 
SQLMenace

another way, this will scan the table only once instead of twice if you use a subquery

only sql server 2005 and up

select Date, User, Status, Notes 
from (
       select m.*, row_number() over (partition by user order by Date desc) as rn
       from [SOMETABLE] m
     ) m2
where m2.rn = 1;

The derived table would work, but if this is SQL 2005, a CTE and ROW_NUMBER might be cleaner:

WITH UserStatus (User, Date, Status, Notes, Ord)
as
(
SELECT Date, User, Status, Notes, 
     ROW_NUMBER() OVER (PARTITION BY User ORDER BY Date DESC)
FROM [SOMETABLE]
)

SELECT User, Date, Status, Notes from UserStatus where Ord = 1

This would also facilitate the display of the most recent x statuses from each user.

Mahesh RG

Another easy way:

SELECT Date, User, Status, Notes  
FROM Test_Most_Recent 
WHERE Date in ( SELECT MAX(Date) from Test_Most_Recent group by User)
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