How to separate scss function returned values

问题

I have two SCSS maps call $my-map-1 and $my-map-2. Each map has the keys with their hex value. I wrote a function to return the key and the hex values ($key, $value) of each map separately.

After that, I wrote a @if condition with my function to check the map. I pass my map name to the function. If map there, check is the $key equal to the given name. If that true, pass the $valu of that $key to my color mixin. This is my code.

$my-map-1: (
        map-1-color-1: #506c89,
        map-1-color-2: #737373,
        map-1-color-3: #2a3949,
        map-1-color-4: #182028,
);

$my-map-2: (
        map-2-color-1: #fff,
        map-2-color-2: #000,
        map-2-color-3: #ddd,
        map-2-color-4: #ccc,
);

//the function to read te map and return the key and the value.
@function color-map($color-map) {
  @each $key, $value in $color-map {    
    @return ($key, $value);
  }
}

//mixin
@mixin color-mix($color){
  color: $color;
}

//css classes from here
@if color-map($my-map-1) {
  if($key == map-1-color-1) {
    .my-class{
      @include color-mix($color:$value);
    }
  }
}

回答1:

You can use map-get method, it is very useful: http://sass-lang.com/documentation/Sass/Script/Functions.html#map_get-instance_method

This is an example of mixin. I pass as argument also your key: maybe it is better because you can check also others key names, if you need it:

$my-map-1: (
  map-1-color-1: #506c89,
  map-1-color-2: #737373,
  map-1-color-3: #2a3949,
  map-1-color-4: #182028
);

$my-map-2: (
  map-2-color-1: #fff,
  map-2-color-2: #000,
  map-2-color-3: #ddd,
  map-2-color-4: #ccc
);


@mixin color-map($color-map, $key-map) {
  @each $key, $value in $color-map {    
    @if($key == $key-map) {
      .my-class{
        color: map-get($color-map, $key);
      }
    }
  }
}

@include color-map($my-map-1, map-1-color-1); 

Your output will be:

.my-class {
  color: #506c89;
}

来源：https://stackoverflow.com/questions/53894589/how-to-separate-scss-function-returned-values