问题
I want to define a special code block, which may starts by any combination of characters of {[<#
, and the end will be }]>#
.
Some example:
{
block-content
}
{##
block-content
##}
#[[<{###
block-content
###}>]]#
Is it possible with petitparser-dart?
回答1:
Yes, back-references are possible, but it is not that straight-forward.
First we need a function that can reverse our delimiter. I came up with the following:
String reverseDelimiter(String token) {
return token.split('').reversed.map((char) {
if (char == '[') return ']';
if (char == '{') return '}';
if (char == '<') return '>';
return char;
}).join();
}
Then we have to declare the stopDelimiter
parser. It is undefined at this point, but will be replaced with the real parser as soon as we know it.
var stopDelimiter = undefined();
In the action of the startDelimiter
we replace the stopDelimiter
with a dynamically created parser as follows:
var startDelimiter = pattern('#<{[').plus().flatten().map((String start) {
stopDelimiter.set(string(reverseDelimiter(start)).flatten());
return start;
});
The rest is trivial, but depends on your exact requirements:
var blockContents = any().starLazy(stopDelimiter).flatten();
var parser = startDelimiter & blockContents & stopDelimiter;
The code above defines the blockContents
parser so that it reads through anything until the matching stopDelimiter
is encountered. The provided examples pass:
print(parser.parse('{ block-content }'));
// Success[1:18]: [{, block-content , }]
print(parser.parse('{## block-content ##}'));
// Success[1:22]: [{##, block-content , ##}]
print(parser.parse('#[[<{### block-content ###}>]]#'));
// Success[1:32]: [#[[<{###, block-content , ###}>]]#]
The above code doesn't work if you want to nest the parser. If necessary, that problem can be avoided by remembering the previous stopDelimiter
and restoring it.
来源:https://stackoverflow.com/questions/21784392/how-to-match-the-start-and-end-of-a-block