问题
I have been trying to understand the TPL Dataflow by creating a sample application. One of thing that I have been trying to do is to update a TextBox
control from ActionBlock
. The reason for using TPL Dataflow is to perform parallel asynchronous operation while keeping the order. The following function is written by me,
private TaskScheduler scheduler = null;
public Form1()
{
this.scheduler = TaskScheduler.FromCurrentSynchronizationContext();
InitializeComponent();
}
public async void btnTPLDataFlow_Click(object sender, EventArgs e)
{
Stopwatch watch = new Stopwatch();
watch.Start();
txtOutput.Clear();
ExecutionDataflowBlockOptions execOptions = new ExecutionDataflowBlockOptions();
execOptions.MaxDegreeOfParallelism = DataflowBlockOptions.Unbounded;
execOptions.TaskScheduler = scheduler;
ActionBlock<int> actionBlock = new ActionBlock<int>(async v =>
{
bool x = await InsertIntoDatabaseAsync(v);
if (x)
txtOutput.Text += "Value Inserted for: " + v + Environment.NewLine;
else
txtOutput.Text += "Value Failed for: " + v + Environment.NewLine;
}, execOptions);
for (int i = 1; i <= 200; i++)
{
actionBlock.Post(i);
}
actionBlock.Complete();
await actionBlock.Completion;
watch.Stop();
lblTPLDataFlow.Text = Convert.ToString(watch.ElapsedMilliseconds / 1000);
}
private async Task<bool> InsertIntoDatabaseAsync(int id)
{
try
{
string connString = "Provider=Microsoft.ACE.OLEDB.12.0;Data Source=D:\\TPLDatabase.accdb;Persist Security Info=False;";
using (OleDbConnection conn = new OleDbConnection(connString))
{
string commandText = "INSERT INTO tblRecords (ProductName, ProductDescription, IsProcessed) VALUES (@ProductName, @ProductDescription, @IsProcessed)";
await conn.OpenAsync();
using (OleDbCommand command = new OleDbCommand(commandText, conn))
{
command.CommandType = CommandType.Text;
command.Parameters.AddWithValue("@ProductName", "Product " + id);
command.Parameters.AddWithValue("@ProductDescription", "Description " + id);
command.Parameters.AddWithValue("@IsProcessed", false);
if (await command.ExecuteNonQueryAsync() > 0)
return true;
else
return false;
}
}
}
catch
{
return false;
}
}
Now the above piece of code runs just fine. It inserts the records in order in my sample MS Access database and updates the UI in order also. But the problem with this is that it blocks the UI which is understandable as I am using the TaskScheduler.FromCurrentSynchronizationContext
which will be updating TextBox
on UI Thread.
I made a small change in the code and remove the scheduler from the ExecutionDataflowBlockOptions
. Instead I update the UI with the following code,
txtOutput.Invoke(new MethodInvoker(delegate
{
if (x)
txtOutput.Text += "Value Inserted for: " + v + Environment.NewLine;
else
txtOutput.Text += "Value Failed for: " + v + Environment.NewLine;
}));
Now this change does not freezes the UI but the order of the values in the database and order of values displayed in TextBox is disturbed badly. The new order is like this,
ID ProductName ProductDescription IsProcessed
6847 Product 6 Description 6 False
6848 Product 7 Description 7 False
6849 Product 8 Description 8 False
6850 Product 10 Description 10 False
6851 Product 11 Description 11 False
6852 Product 12 Description 12 False
6853 Product 9 Description 9 False
6854 Product 13 Description 13 False
6855 Product 14 Description 14 False
Now what can be the best way to update the UI in my scenario and also keeping the order.
回答1:
TPL Dataflow blocks preserve the order of the input when they output. They don't preserve the order of execution while inside the block, that's why you see everything out of order.
What you probably want to do is replace the ActionBlock
with a TransformBlock
to actually do the hard work concurrently and link it with an ActionBlock
that updates the UI one at a time.
You can also have this block run on the UI thread so you wouldn't need to use Invoke
:
var transformBlock = new TransformBlock<int, int>(
v => InsertIntoDatabaseAsync(v),
execOptions);
var actionBlock = new ActionBlock<int>(x =>
{
if (x)
txtOutput.Text += "Value Inserted for: " + v + Environment.NewLine;
else
txtOutput.Text += "Value Failed for: " + v + Environment.NewLine;
}, new ExecutionDataflowBlockOptions { TaskScheduler = TaskScheduler.FromCurrentSynchronizationContext() })
transformBlock.LinkTo(ActionBlock, new DataflowLinkOptions { PropagateCompletion = true } );
来源:https://stackoverflow.com/questions/32089932/updating-ui-control-from-actionblock