问题
I need a fast method to store all samples of a wav file in an array. I am currently working around this problem by playing the music and storing the values from the Sample Provider, but this is not very elegant.
From the NAudio Demo I have the Audioplayer Class with this Method:
private ISampleProvider CreateInputStream(string fileName)
{
if (fileName.EndsWith(".wav"))
{
fileStream = OpenWavStream(fileName);
}
throw new InvalidOperationException("Unsupported extension");
}
var inputStream = new SampleChannel(fileStream, true);
var sampleStream = new NotifyingSampleProvider(inputStream);
SampleRate = sampleStream.WaveFormat.SampleRate;
sampleStream.Sample += (s, e) => { aggregator.Add(e.Left); }; // at this point the aggregator gets the current sample value, while playing the wav file
return sampleStream;
}
I want to skip this progress of getting the sample values while playing the file, instead I want the values immediatly without waiting till the end of the file. Basically like the wavread command in matlab.
回答1:
Use AudioFileReader
to read the file. This will automatically convert to IEEE float samples. Then repeatedly call the Read
method to read a block of samples into a float[] array.
来源:https://stackoverflow.com/questions/15419446/storing-a-wav-file-in-an-array