问题
I've got a snippet of IDL that looks like this:
[ object, uuid(...), pointer_default(unique) ]
interface IVirtualMachine { /* ... */ }
[ object, uuid(...), pointer_default(unique) ]
interface IVirtualServer : IUnknown
{
HRESULT FindVirtualMachine(
[in] BSTR configurationName,
[out,retval] IVirtualMachine **virtualMachine);
};
[ uuid(...), version(1.0) ]
library VirtualServerLib
{
[ uuid(...) ]
coclass VirtualServer
{
[default] interface IVirtualServer;
};
[ uuid(...) ]
coclass VirtualMachine
{
[default] interface IVirtualMachine;
};
};
...when I compile it with MIDL and then look in the generated type library, VirtualMachine
(upper-case V) has been turned into virtualMachine
(lower-case V).
If I call my coclass XirtualMachine
, for example, it's all good.
What the hell?
回答1:
This is a terrible bug/feature of MIDL. It doesn't allow the same identifier to appear with different casing, so it replaces all subsequent instances of a word with the casing from the first time it was seen.
See the KB220137
回答2:
OK. Worked it out. It was this line here:
[out,retval] IVirtualMachine **virtualMachine);
If I change it to:
[out,retval] IVirtualMachine **ppVirtualMachine);
...then it works fine. Something screwy in MIDL, I guess. Maybe it's trying to do VB-like case correction.
来源:https://stackoverflow.com/questions/1278166/midl-changes-case-of-identifier-when-compiling-idl-file