问题
I am currently trying to figure out the best way to select all items in a list that are currently visible.
I currently have a large list of items in my scope that has paging applied to it so only a few items of this list are visible at a time. I have a "Select All" button where the desired behavior is to have it select all the items that are currently visible - not all the items in the list.
I think I can achieve it by using the ng-init directive to add visible items to a list in the controller, I can then use that list to see what is visible. To me it seems that there has to be a better solution that I am missing.
Does anyone have a elegant solution to this?
回答1:
Not the clearest of questions, but I assume you're using an ng-repeat with some sort of filter that's knocking down the items to only the ones you want to show. You can set an inline scope variable when declaring your ng-repeat and work off of that.
So if your html looks like this:
<div ng-repeat="item in items | someFilter"></div>
You can change it to:
<div ng-repeat="item in visibleItems = (items | someFilter)"></div>
Then you can use $scope.visibleItems inside your controller and it will only contain the certain subset of items that have passed your someFilter.
来源：https://stackoverflow.com/questions/23704743/angularjs-select-all-items-that-are-currently-visible