Understanding loops performance in jvm

问题

I'm playing with jmh and in the section about looping they said that

You might notice the larger the repetitions count, the lower the "perceived" cost of the operation being measured. Up to the point we do each addition with 1/20 ns, well beyond what hardware can actually do. This happens because the loop is heavily unrolled/pipelined, and the operation to be measured is hoisted from the loop. Morale: don't overuse loops, rely on JMH to get the measurement right.

I tried it myself

    @Benchmark
    @OperationsPerInvocation(1)
    public int measurewrong_1() {
        return reps(1);
    }      

    @Benchmark
    @OperationsPerInvocation(1000)
    public int measurewrong_1000() {
        return reps(1000);
    }

and got the following result:

Benchmark                      Mode  Cnt  Score    Error  Units
MyBenchmark.measurewrong_1     avgt   15  2.425 ±  0.137  ns/op
MyBenchmark.measurewrong_1000  avgt   15  0.036 ±  0.001  ns/op

It indeed shows that the MyBenchmark.measurewrong_1000 is dramatically faster than MyBenchmark.measurewrong_1. But I cannot really understand the optimization JVM does to make this performance improvement.

What do they mean the loop is unrolled/pipelined?

回答1:

Loop unrolling makes pipelining possible. So the pipeline-able CPU (for example RISC) can execute the unrolled code in parallel.

So if your CPU is able to execute 5 pipelines in parallel, your loop will be unrolled in the way:

// pseudo code
int pipelines = 5;
for(int i = 0; i < length; i += pipelines){
    s += (x + y);
    s += (x + y);
    s += (x + y);
    s += (x + y);
    s += (x + y);
}

IF = Instruction Fetch, ID = Instruction Decode, EX = Execute, MEM = Memory access, WB = Register write back

From Oracle White paper:

... a standard compiler optimization that enables faster loop execution. Loop unrolling increases the loop body size while simultaneously decreasing the number of iterations. Loop unrolling also increases the effectiveness of other optimizations.

more information about pipelining: Classic RISC pipeline

回答2:

Loop unrolling is a tecnhique to flatten multiple loop iterations by repeating the loop body.
E.g. in the given example

    for (int i = 0; i < reps; i++) {
        s += (x + y);
    }

can be unrolled by JIT compiler to something like

    for (int i = 0; i < reps - 15; i += 16) {
        s += (x + y);
        s += (x + y);
        // ... 16 times ...
        s += (x + y);
    }

Then the extended loop body can be further optimized to

    for (int i = 0; i < reps - 15; i += 16) {
        s += 16 * (x + y);
    }

Obviously computing 16 * (x + y) is much faster than computing (x + y) 16 times.

回答3:

Loop Pipelining = Software Pipelining.

Basically, it's a technique that is used to optimize the efficiency of sequential loop iterations, by executing some of the instructions in the body of the loop - in parrallel.

Of course, this can be done only when certain conditions are met, such as each iteration not being dependent on another etc.

From insidehpc.com:

Software pipelining, which really has nothing to do with hardware pipelining, is a loop optimization technique to make statements within an iteration independent of each other. The goal is to remove dependencies so that seemingly sequential instructions may be executed in parallel.

See more here:

Sofware pipelining explained
Software pipelining - Wikipedia

来源：https://stackoverflow.com/questions/40305266/understanding-loops-performance-in-jvm

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java

performance

loops

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