问题
I'm having trouble using map::emplace()
. Can anyone help me figure out the right syntax to use? I am effectively trying to do the same thing as in this example. Here is my version:
#include <map>
using namespace std;
class Foo
{
// private members
public:
Foo(int, char, char) /* :init(), members() */ { }
// no default ctor, copy ctor, move ctor, or assignment
Foo() = delete;
Foo(const Foo&) = delete;
Foo(Foo &&) = delete;
Foo & operator=(const Foo &) = delete;
Foo & operator=(Foo &&) = delete;
};
int main()
{
map<int, Foo> mymap;
mymap.emplace(5, 5, 'a', 'b');
return 0;
}
Under GCC 4.7 (with the -std=c++11
flag), I am erroring out on the emplace
line. The example I linked above doesn't say anything about how to deal with custom types instead of primitives.
回答1:
A container's emplace
member constructs an element using the supplied arguments.
The value_type
of your map is std::pair<const int, Foo>
and that type has no constructor taking the arguments { 5, 5, 'a', 'b' }
i.e. this wouldn't work:
std::pair<const int, Foo> value{ 5, 5, 'a', 'b' };
map.emplace(value);
You need to call emplace
with arguments that match one of pair
's constructors.
With a conforming C++11 implementation you can use:
mymap.emplace(std::piecewise_construct, std::make_tuple(5), std::make_tuple(5, 'a', 'b'));
but GCC 4.7 doesn't support that syntax either (GCC 4.8 will when it's released.)
回答2:
GCC 4.7 does not have full support of emplace
functions.
You can see C++11 support in GCC 4.7.2 here.
来源:https://stackoverflow.com/questions/14075128/mapemplace-with-a-custom-value-type