googlemock - mock a method that returns a complex datatyp

问题

I want to mock a method that returns a complex datatyp

class aClass
{
public:
   virtual const QMap<QString, QString> aMethod() const;
}

class MockaClass : public aClass
{
public:
   MOCK_CONST_METHOD0(aMethod, const QMap<QString, QString>());
}

This code does not compile: "macro "MOCK_CONST_METHOD0" passed 3 arguments, but takes just 2"

I think that the googlemock macro does not understand QMap and interpret the comma as parameter separator.

Is there a way to tell googlemock that QMap is the return value?

回答1:

Just use a typedef like this:

class aClass
{
public:
   typedef const QMap<QString, QString> MyType;
   virtual MyType aMethod() const;
}

class MockaClass : public aClass
{
public:
   MOCK_CONST_METHOD0(aMethod, MyType());
}

回答2:

You are right, the comma is interpreted as a parameter separator. You can define a preprocessor macro to protect the comma from being interpreted that way.

#define COMMA ,
MOCK_CONSTANT_METHOD0(aMethod, const QMap<QString COMMA QString>());

Please note, that this will not necessarily work for nested macro calls. For example, if MOCK_CONSTANT_METHOD0 would pass the second parameter to another macro, you would be in trouble again.

来源：https://stackoverflow.com/questions/10207490/googlemock-mock-a-method-that-returns-a-complex-datatyp