问题
I'm trying to figure out how to deserialize JSON into a structure using Serde. For instance, the example JSON on serde_json's own documentation contains the following data:
{
"FirstName": "John",
"LastName": "Doe",
"Age": 43,
"Address": {
"Street": "Downing Street 10",
"City": "London",
"Country": "Great Britain"
},
"PhoneNumbers": [
"+44 1234567",
"+44 2345678"
]
}
Now, if we assume that the above data is in a variable "input" and the following piece of code:
let deserialized_data: Data = serde_json::from_str(input).unwrap();
... what should struct Data
look like?
回答1:
Most of the standard data structures are serializable, so the following structures should work:
#[derive(Serialize, Deserialize)]
struct Data {
FirstName: String,
LastName: String,
Age: u32,
Address: Address,
PhoneNumbers: Vec<String>
}
#[derive(Serialize, Deserialize)]
struct Address {
Street: String,
City: String,
Country: String
}
If some of the fields in input may be absent, then the corresponding structure fields should be Option<T>
instead of just T
.
Note that it is possible to name fields in a more "Rusty" manner, i.e. snake_case, because serde supports renaming annotations:
#[derive(Serialize, Deserialize)]
struct Address {
#[serde(rename="Street")]
street: String,
#[serde(rename="City")]
city: String,
#[serde(rename="Country")]
country: String
}
This issue is also relevant to fields renaming.
来源:https://stackoverflow.com/questions/33251881/rust-serde-json-deserialization-examples