Ruby regex for matching simpliest Ruby's regexes

自作多情 提交于 2019-12-08 08:21:04

问题


I want to match regexes (at least the basic ones, not all their possible kinds... for now...) in a text of Ruby script.
It's something like a... \/\^? oh my god... \$?\/[eimnosux]*

Maybe I need recursive regex here.


回答1:


As I commented above, you'll need to parse Ruby to differentiate division slashes and regex delimiters. But for the simplest, SIMPLEST case without worrying about this, how about:

regex_match = %r{/(?:[^/\\]|\\.)+/[mgixo]*}

That is "A forward slash, followed by one or more things that either aren't a forward slash or a backslash, or are a backslash followed by something else, finally followed by a slash, and possibly some regex flags."



来源:https://stackoverflow.com/questions/4206838/ruby-regex-for-matching-simpliest-rubys-regexes

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