I am trying to write a function to find the gcd of 2 numbers, using Euclid's Algorithm which I found here.
From the larger number, subtract the smaller number as many times as you can until you have a number that is smaller than the small number. (or without getting a negative answer) Now, using the original small number and the result, a smaller number, repeat the process. Repeat this until the last result is zero, and the GCF is the next-to-last small number result. Also see our Euclid's Algorithm Calculator.
Example: Find the GCF (18, 27)
27 - 18 = 9
18 - 9 = 9
9 - 9 = 0
So, the greatest common factor of 18 and 27 is 9, the smallest result we had before we reached 0.
Following these instructions I wrote a function:
int hcf(int a, int b)
{
int small = (a < b)? a : b;
int big = (a > b)? a : b;
int res;
int gcf;
cout << "small = " << small << "\n";
cout << "big = " << big << "\n";
while ((res = big - small) > small && res > 0) {
cout << "res = " << res << "\n";
}
while ((gcf = small - res) > 0) {
cout << "gcf = " << gcf << "\n";
}
return gcf;
}
However, the second loop seems to be infinite. Can anyone explain why?
I know the website actually shows the code(PHP), but I'm trying to write this code using only the instructions they give.
Of course this loop is infinite:
while ((gcf = small - res) > 0) {
cout << "gcf = " << gcf << "\n";
}
small
and res
don't change in the loop, so gcf
doesn't either. That loop is equivalent to:
gcf = small - res;
while (gcf > 0) {
cout << "gcf = " << gcf << "\n";
}
which is probably more clear.
I would port that algorithm to code as follows:
int gcd(int a, int b) {
while (a != b) {
if (a > b) {
a -= b;
}
else {
b -= a;
}
}
return a;
}
Although typically gcd
is implemented using mod, since it's much faster:
int gcd(int a, int b) {
return (b == 0) ? a : gcd(b, a % b);
}
来源:https://stackoverflow.com/questions/28267611/using-euclid-algorithm-to-find-gcfgcd