How can I implement CBC-MAC with DES?

主宰稳场 提交于 2019-12-08 02:39:46

问题


I should implement a MAC-CBC generation method in C# with some information about the cryptography algorithm. Here's what I have:

  • I should use DES.
  • The key is byte[] {11, 11, 11, 11, 11, 11, 11, 11}
  • The data (16 bytes) should be encrypted in 8-byte parts. First 8 bytes is encrypted using Instance Vector = new byte[8] (8 bytes with 0 value). (CBC?)
  • that last 8 bytes of the encrypted value should be converted to Hex string. this is the result I should send.

With this information, I have implemented the following method:

public static string Encrypt(byte[] data)
{
    var IV = new byte[8];
    var key = new byte[] { 11, 11, 11, 11, 11, 11, 11, 11 };
    var result = new byte[16];

    // Create DES and encrypt.
    var des = DES.Create();
    des.Key = key;
    des.IV = IV;
    des.Padding = PaddingMode.None;
    des.Mode = CipherMode.CBC;
    ICryptoTransform cryptoTransform = des.CreateEncryptor(key, IV);
    cryptoTransform.TransformBlock(data, 0, 16, result, 0);

    // Get the last eight bytes of the encrypted data.
    var lastEightBytes = new byte[8];
    Array.Copy(result, 8, lastEightBytes, 0, 8);

    // Convert to hex.
    var hexResult = string.Empty;
    foreach (byte ascii in lastEightBytes)
    {
        int n = (int)ascii;
        hexResult += n.ToString("X").PadLeft(2, '0');
    }

    return hexResult;
}

The sample raw data they have provided me is: input=byte[] {0, 6, 4, 1, 6, 4, 1, 7, E, E, F, F, F, F, B, B) which should return the output of value: A7CBFB3C730B059C. This means the last eight bytes of encrypted data should be: byte[] {167, 203, 251, 60, 115, 11, 05, 156}.

But unfortunately using the above method, I get: 32D91200D0007632. meaning my encrypted data is not correct. (the last eight byte of my method's generated encrypted value is byte[] {50, 207, 18, 0, 208, 0, 118, 50}).

Is there any way that I can find out what I should do to get to A7CB...? Am I doing something wrong?


回答1:


CBC-MAC requires a zero Initialisation Vector. Much better to specify the IV explicitly:

var IV = new byte[] { 0, 0, 0, 0, 0, 0, 0, 0 };  

You say your key is byte[] { 11, 11, 11, 11, 11, 11, 11, 11 } are those bytes in hex or in base 10? You might want to try:

var key = new byte[] { 0x11, 0x11, 0x11, 0x11, 0x11, 0x11, 0x11, 0x11 };

and see if that works better.




回答2:


The Mono project has a generic MAC-CBC implementation that should work on any SymmetricAlgorithm - even if it's used, internally, only to implement MACTripleDES.

You can find the MIT.X11 licensed source code here. Use it as-is or compare it to your own code.



来源:https://stackoverflow.com/questions/7631998/how-can-i-implement-cbc-mac-with-des

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