Generating a ECDSA Private key in bouncy castle returns a PUBLIC key

纵饮孤独 提交于 2019-12-07 15:03:48

问题


I am attempting to use bouncy castle to generate ECDSA keys. The code seems to work fine from the Java perspective; but, when I dump the file and try to validate the data, OpenSSL does not like the format of the data.

After some research, I figured that bouncy castle is encoding the private key as public key.

Here is my Java code:

public class Test {
    public static void main(String[] args) {
        Security.addProvider(new BouncyCastleProvider());
        System.out.println("Starting...");
        String name = "prime256v1";
        try {
            KeyPairGenerator kpg = KeyPairGenerator.getInstance("ECDSA", BouncyCastleProvider.PROVIDER_NAME);
            kpg.initialize(new ECGenParameterSpec(name));
            KeyPair keyPair = kpg.generateKeyPair();    
            FileOutputStream writer = new FileOutputStream("private.key");
            writer.write(keyPair.getPrivate().getEncoded());
            writer.close();
        } catch(Exception e) {
            e.printStackTrace();
        }
    }
}

The file private.key is generated in valid DER format; however, when I run the following command to see the ASN.1 structure of the key:

$ openssl asn1parse -inform DER -in /my/path/private.key
    0:d=0  hl=3 l= 147 cons: SEQUENCE          
    3:d=1  hl=2 l=   1 prim: INTEGER           :00
    6:d=1  hl=2 l=  19 cons: SEQUENCE          
    8:d=2  hl=2 l=   7 prim: OBJECT            :id-ecPublicKey
   17:d=2  hl=2 l=   8 prim: OBJECT            :prime256v1
   27:d=1  hl=2 l= 121 prim: OCTET STRING      [HEX DUMP]: <hex data>

For comparison, if I run the following commands to generate a ECDSA key using OpenSSL, I get the following ASN.1 structure:

 $ openssl ecparam -name prime256v1 -genkey -noout -outform DER -out private.key
 $ openssl asn1parse -inform DER -in private.key
     0:d=0  hl=2 l= 119 cons: SEQUENCE          
     2:d=1  hl=2 l=   1 prim: INTEGER           :01
     5:d=1  hl=2 l=  32 prim: OCTET STRING      [HEX DUMP]: <hex data>
    39:d=1  hl=2 l=  10 cons: cont [ 0 ]        
    41:d=2  hl=2 l=   8 prim: OBJECT            :prime256v1
    51:d=1  hl=2 l=  68 cons: cont [ 1 ]        
    53:d=2  hl=2 l=  66 prim: BIT STRING        

So, I guess my questions are

  • Is there anything I am missing?
  • Or is this a known bug?
  • Is there anyway to get around it?

回答1:


Java outputs key in the encoded format. You should try:

private String getPrivateKeyAsHex(PrivateKey privateKey) {

    ECPrivateKey ecPrivateKey = (ECPrivateKey) privateKey;
    byte[] privateKeyBytes = new byte[PRIVATE_KEY_LENGTH];
    writeToStream(privateKeyBytes, 0, ecPrivateKey.getS(), PRIVATE_KEY_LENGTH);

    String hex = Hex.toHexString(privateKeyBytes);

    logger.debug("Private key bytes: " + Arrays.toString(privateKeyBytes));
    logger.debug("Private key hex: " + hex);

    return hex;
}

private String getPublicKeyAsHex(PublicKey publicKey) {

    ECPublicKey ecPublicKey = (ECPublicKey) publicKey;
    ECPoint ecPoint = ecPublicKey.getW();

    byte[] publicKeyBytes = new byte[PUBLIC_KEY_LENGTH];
    writeToStream(publicKeyBytes, 0, ecPoint.getAffineX(), PRIVATE_KEY_LENGTH);
    writeToStream(publicKeyBytes, PRIVATE_KEY_LENGTH, ecPoint.getAffineY(), PRIVATE_KEY_LENGTH);

    String hex = Hex.toHexString(publicKeyBytes);

    logger.debug("Public key bytes: " + Arrays.toString(publicKeyBytes));
    logger.debug("Public key hex: " + hex);

    return hex;
}

private void writeToStream(byte[] stream, int start, BigInteger value, int size) {
    byte[] data = value.toByteArray();
    int length = Math.min(size, data.length);
    int writeStart = start + size - length;
    int readStart = data.length - length;
    System.arraycopy(data, readStart, stream, writeStart, length);
}


来源:https://stackoverflow.com/questions/40552688/generating-a-ecdsa-private-key-in-bouncy-castle-returns-a-public-key

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