问题
Why does this code result in a run-time error "vector iterator not incrementable"?
vector<string> s1, s2;
s1.push_back("joe");
s1.push_back("steve");
s1.push_back("jill");
s1.push_back("svetlana");
s2.push_back("bob");
s2.push_back("james");
s2.push_back("jill");
s2.push_back("barbara");
s2.push_back("steve");
sort(s1.begin(), s1.end());
sort(s2.begin(), s2.end());
vector<string> result;
vector<string>::iterator it_end, it_begin;
it_end = set_intersection(s1.begin(), s1.end(), s2.begin(), s2.end(), result.begin());
cout << int (it_end - result.begin()) << endl;
for_each(result.begin(), result.end(), print);
回答1:
result.begin()
of an empty vector is not a valid output iterator. You need a back_inserter(result) instead.
#include <iterator>
...
set_intersection(s1.begin(), s1.end(), s2.begin(), s2.end(), back_inserter(result));
cout << result.size() << endl;
Alternatively, resize result
to at least 4, so that the vector can contain all results.
来源:https://stackoverflow.com/questions/3477955/vector-iterator-not-incrementable-run-time-error-with-set-intersection