问题
Please help interpret the Birthday effect as described in Wikipedia:
A birthday attack works as follows:
- Pick any message m and compute h(m).
- Update list L. Check if h(m) is in the list L.
- if (h(m),m) is already in L, a colliding message pair has been found. else save the pair (h(m),m) in the list L and go back to step 1.
From the birthday paradox we know that we can expect to find a matching entry, after performing about 2^(n/2) hash evaluations.
Does the above mean 2^(n/2) iterations through the above entire loop (i.e. 2^(n/2) returns to step 1), OR does it mean 2^(n/2) comparisons to individual items already in L?
回答1:
It means 2^(n/2) iterations through the loop. But note that L would not be a normal list here, but a hash table mapping h(m) to m. So each iteration would only need a constant number (O(1)) of comparisons in average, and there would be O(2^(n/2)) comparisons in total.
If L had been a normal array or a linked list, then the number of comparisons would be much larger since you would need to search through the whole list each iteration. This would be a bad way to implement this algorithm though.
来源：https://stackoverflow.com/questions/2766910/can-someone-please-clarify-the-birthday-effect-for-me