I've a linux application that links against a static library (.a) and that library uses the dlopen function to load dynamic libraries (.so)
If I compile the static library as dynamic and link it to the application, the dlopen it will work as expected, but if I use it as described above it won't.
Can't a static library uses the dlopen function to load shared libraries?
Thanks.
There should be no problem with what you're trying to do:
app.c:
#include "staticlib.h"
#include "stdio.h"
int main()
{
printf("and the magic number is: %d\n",doSomethingDynamicish());
return 0;
}
staticlib.h:
#ifndef __STATICLIB_H__
#define __STATICLIB_H__
int doSomethingDynamicish();
#endif
staticlib.c:
#include "staticlib.h"
#include "dlfcn.h"
#include "stdio.h"
int doSomethingDynamicish()
{
void* handle = dlopen("./libdynlib.so",RTLD_NOW);
if(!handle)
{
printf("could not dlopen: %s\n",dlerror());
return 0;
}
typedef int(*dynamicfnc)();
dynamicfnc func = (dynamicfnc)dlsym(handle,"GetMeANumber");
const char* err = dlerror();
if(err)
{
printf("could not dlsym: %s\n",err);
return 0;
}
return func();
}
dynlib.c:
int GetMeANumber()
{
return 1337;
}
and build:
gcc -c -o staticlib.o staticlib.c
ar rcs libstaticlib.a staticlib.o
gcc -o app app.c libstaticlib.a -ldl
gcc -shared -o libdynlib.so dynlib.c
First line builds the lib
second line packs it into a static lib
third builds the test app, linking in the newly created static, plus the linux dynamic linking library(libdl)
fourth line builds the soon-to-be-dynamically-loaded shared lib.
output:
./app
and the magic number is: 1337
来源:https://stackoverflow.com/questions/17862272/dlopen-a-dynamic-library-from-a-static-library-linux-c