I am working on a small XSLT file to copy the contents of an XML file and strip out the declaration and root node. The root node has an namespace attribute.
I currently have it working except for now the namespace attribute is now being copied to the direct children nodes.
Here is my xslt file so far, nothing big or complicated:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" omit-xml-declaration="yes" encoding="utf-8"/>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/*">
<xsl:apply-templates select="node()" />
</xsl:template>
</xsl:stylesheet>
My input file is like this:
<?xml version="1.0" encoding="UTF-8"?>
<Report_Data xmlns="examplenamespace">
<Report_Entry>
<Report_Date>
</Report_Date>
</Report_Entry>
<Report_Entry>
<Report_Date>
</Report_Date>
</Report_Entry>
<Report_Entry>
<Report_Date>
</Report_Date>
</Report_Entry>
</Report_Data>
The output after the XSLT is like this:
<Report_Entry xmlns="examplenamespace">
<Report_Date>
</Report_Date>
</Report_Entry>
<Report_Entry xmlns="examplenamespace">
<Report_Date>
</Report_Date>
</Report_Entry>
<Report_Entry xmlns="examplenamespace">
<Report_Date>
</Report_Date>
</Report_Entry>
The problem is, every Report_Entry tag is now getting that xml namespace attribute from the root node that I removed.
In case you were wondering, I know the output of the XSLT is not well formed. I am adding the XML declaration and a different root node name later on after the XSLT trasnformation.
The following produces the output that you want:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" omit-xml-declaration="yes" encoding="utf-8"/>
<!-- For each element, create a new element with the same local-name (no namespace) -->
<xsl:template match="*">
<xsl:element name="{local-name()}">
<xsl:copy-of select="@*"/>
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
<!-- Skip the root element, just process its children. -->
<xsl:template match="/*">
<xsl:apply-templates/>
</xsl:template>
</xsl:stylesheet>
来源:https://stackoverflow.com/questions/19733948/copy-xml-file-contents-except-for-root-node-and-attribute-xslt