I believe it's possible but couldn't figure out the syntax. Something like this:
xmlNode.SelectNodes("//*[count(child::*) <= 1]")
but this is not correct.
Use:
//node()[not(node())]
In case only element leaf nodes are wanted (and this needs clarification -- are elements that have non-element children considered leaf nodes?), then the following XPath expression selects them:
//*[not(*)]
Both expressions above are probably the shortest that select the desired nodes (either any-node or element -- leaf nodes).
Any elements with no element child
//*[not(child::*)]
Why less or equal to 1 ?
xmlNode.SelectNodes("//*[count(child::*) = 0]")
Make tests etc at this site http://www.whitebeam.org/library/guide/TechNotes/xpathtestbed.rhtm
Pretty helpful ..
I'm adding this XSLT answer since it seems google's front matches lack such a solution:
After a long struggle with extracting CDATA as XML, eventually, this expression worked best for me:
<xsl:template match="*[not(child::*)]/text()">
来源:https://stackoverflow.com/questions/3926589/how-to-select-all-leaf-nodes-using-xpath-expression