Is the .Net HashSet uniqueness calculation completely based on Hash Codes?

痞子三分冷 提交于 2019-12-05 00:15:14

No, it uses equality as well. By definition, hash codes don't need to be unique - anything which assumes they will be is broken. HashSet<T> is sensible. It uses an IEqualityComparer<T> (defaulting to EqualityComparer<T>.Default) to perform both hash code generation and equality tests.

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