问题
I had asked the question previously about how to retrieve the embedded url for a video file and have successfully done so. Now I have a different issue. The json response for a WUnderground API webcam response gives the following url:
https://www.wunderground.com/webcams/cadot1/902/show.html
Using JSoup and per the answer to my initial issue I was able to get this embedded link:
https://www.wunderground.com/webcams/cadot1/902/video.html?month=11&year=2016&filename=current.mp4
While trying to "stream" the video from that url to a VideoView, I kept getting the error "cannot play video". Upon looking at the source for that link I noticed that the video file that needs to be played is not referenced in html but rather javascript. How can I get the direct link for the video file that needs to be played? Using JSoup or other process?
The source for the url https://www.wunderground.com/webcams/cadot1/902/video.html?month=11&year=2016&filename=current.mp4
shows the following for the needed video file within a <script>
bracket:
url: "//icons.wunderground.com/webcamcurrent/c/a/cadot1/902/current.mp4?e=1480377508"
I am using JSoup to get the embedded url for the video from the response url like so:
private class VideoLink extends AsyncTask<Void, Void, Void> {
String title;
@Override
protected void onPreExecute() {
super.onPreExecute();
mProgressDialog.setTitle("JSOUP Test");
mProgressDialog.setMessage("Loading...");
mProgressDialog.setIndeterminate(false);
mProgressDialog.show();
}
@Override
protected Void doInBackground(Void... params) {
try {
// for avoiding javax.net.ssl.SSLProtocolException: handshake alert: unrecognized_name
System.setProperty("jsse.enableSNIExtension", "false");
// WARNING: do it only if security isn't important, otherwise you have
// to follow this advices: http://stackoverflow.com/a/7745706/1363265
// Create a trust manager that does not validate certificate chains
TrustManager[] trustAllCerts = new TrustManager[]{new X509TrustManager(){
public X509Certificate[] getAcceptedIssuers(){return null;}
public void checkClientTrusted(X509Certificate[] certs, String authType){}
public void checkServerTrusted(X509Certificate[] certs, String authType){}
}};
// Install the all-trusting trust manager
try {
SSLContext sc = SSLContext.getInstance("TLS");
sc.init(null, trustAllCerts, new SecureRandom());
HttpsURLConnection.setDefaultSSLSocketFactory(sc.getSocketFactory());
} catch (Exception e) {
;
}
// Connect to the web site
Document doc = Jsoup.connect(TEST_URL).get();
Elements elements = doc.getElementsByClass("videoText");
// Get the html document title
for (Element link : elements) {
String linkHref = link.attr("href");
// linkHref contains something like video.html?month=11&year=2016&filename=current.mp4
// TODO check if linkHref ends with current.mp4
title = linkHref;
}
} catch (IOException e) {
e.printStackTrace();
mProgressDialog.dismiss();
}
return null;
}
@Override
protected void onPostExecute(Void result) {
// Set title into TextView
resultTxt.setText(title);
String resVid = TEST_URL;
Log.d(TAG, "URL: " + resVid);
Uri resUri = Uri.parse(resVid);
try {
// Start the MediaController
MediaController mediacontroller = new MediaController(
MainActivity.this);
mediacontroller.setAnchorView(resultVidVw);
// Get the URL from String VideoURL
Uri video = Uri.parse(resVid);
resultVidVw.setMediaController(mediacontroller);
resultVidVw.setVideoURI(video);
} catch (Exception e) {
Log.e("Error", e.getMessage());
e.printStackTrace();
}
resultVidVw.requestFocus();
resultVidVw.setOnPreparedListener(new MediaPlayer.OnPreparedListener() {
// Close the progress bar and play the video
public void onPrepared(MediaPlayer mp) {
mProgressDialog.dismiss();
resultVidVw.start();
}
});
}
}
Please note that I need to do this on every JSONObject in the response array.
回答1:
This is how you can GET the file:
(Notice: the Extraction part only works with current html of the site and if that changes, it may not work correctly!)
String url = "https://www.wunderground.com/webcams/cadot1/902/video.html";
int timeout = 100 * 1000;
// Extract video URL
Document doc = Jsoup.connect(url).timeout(timeout).get();
Element script = doc.getElementById("inner-content")
.getElementsByTag("script").last();
String content = script.data();
int indexOfUrl = content.indexOf("url");
int indexOfComma = content.indexOf(',', indexOfUrl);
String videoUrl = "https:" + content.substring(indexOfUrl + 6, indexOfComma - 1);
System.out.println(videoUrl);
[Output: https://icons.wunderground.com/webcamcurrent/c/a/cadot1/902/current.mp4?e=1481246112
]
Now you can get the file by specifying .ignoreContentType(true)
in order to avoid org.jsoup.UnsupportedMimeTypeException
and .maxBodySize(0)
to remove the limit on file size.
// Get video file
byte[] video = Jsoup.connect(videoUrl)
.ignoreContentType(true).timeout(timeout).maxBodySize(0)
.execute().bodyAsBytes();
I don't know if you can play it in Android or not but I think you can save it using org.apache.commons.io.FileUtils
(I tested it in Java SE but not Android development environment.)
// Save video file
org.apache.commons.io.FileUtils.writeByteArrayToFile(new File("test.mp4"), video);
来源:https://stackoverflow.com/questions/40858581/how-to-get-direct-link-of-remote-video-from-embedded-url-within-a-url-in-android