问题
Let's say I have these template aliases:
enum class enabler {};
template <typename T>
using EnableIf = typename std::enable_if<T::value, enabler>::type;
template <typename T>
using DisableIf = typename std::enable_if<!T::value, enabler>::type;
I can do the following in GCC:
#include <iostream>
template <typename T, EnableIf<std::is_polymorphic<T>> = {}>
void f(T) { std::cout << "is polymorphic\n"; }
template <typename T, DisableIf<std::is_polymorphic<T>> = {}>
void f(T) { std::cout << "is not polymorphic\n"; }
struct foo { virtual void g() {} };
int main() {
f(foo {});
f(int {});
}
It prints:
is polymorphic
is not polymorphic
Which matches my expectations.
With clang that code does not compile. It produces the following error messages.
test.cpp:11:58: error: expected expression
template <typename T, EnableIf<std::is_polymorphic<T>> = {}>
^
test.cpp:14:59: error: expected expression
template <typename T, DisableIf<std::is_polymorphic<T>> = {}>
^
test.cpp:20:3: error: no matching function for call to 'f'
f(foo {});
^
test.cpp:12:6: note: candidate template ignored: couldn't infer template argument ''
void f(T) { std::cout << "is polymorphic\n"; }
^
test.cpp:15:6: note: candidate template ignored: couldn't infer template argument ''
void f(T) { std::cout << "is not polymorphic\n"; }
^
test.cpp:21:3: error: no matching function for call to 'f'
f(int {});
^
test.cpp:12:6: note: candidate template ignored: couldn't infer template argument ''
void f(T) { std::cout << "is polymorphic\n"; }
^
test.cpp:15:6: note: candidate template ignored: couldn't infer template argument ''
void f(T) { std::cout << "is not polymorphic\n"; }
^
4 errors generated.
Should it compile? Which of the two compilers is faulty?
回答1:
First and foremost, thanks to @Richard Smith on the #llvm IRC Channel on oftc for the explanation.
Unfortunately, this is not legal C++ and as such Clang is correct: {}
is not an expression but a braced-init-list and as such will never be a constant expression as is needed in the initializer of a non-type template parameter.
§14.3.2 [temp.arg.non-type] p1
A template-argument for a non-type, non-template template-parameter shall be one of:
- for a non-type template-parameter of integral or enumeration type, a converted constant expression (5.19) of the type of the template-parameter; or
- [...]
One solution would be a dummy value in enabler
.
来源:https://stackoverflow.com/questions/10180552/is-substitution-failure-an-error-with-dependent-non-type-template-parameters